What conclusion can be obtained on the basis of following electrochemical cell `M|M^(+)||X^(-)|X,E_(M^(+)|M)^(o)=0.44V and E_(X|X^(-))^(o)=0.33V`.

Options

A. `M^(+)+X^(-) to M+X` is spontaneous reaction
B. `M+X to M^(+)+X^(-)` is spontaneous reaction
C. `E_(cell)=0.11V`
D. `E_(cell)=-0.11V`.

Answer

A

Explanation

`E_(M^(+)|M)^(o)=0.44V`
Cathode in half-cell: `underset(("Reactant"))(M^(+))+e^(-) to underset(("Product"))(M)` . . . Reduction
`therefore E_(M|M^(+))^(o)` (Oxidation potential)=-0.44 V
`E_(X|X^(-))^(o)=0.33V`
`X^(-) to X+e^(-)` (Oxidation) and
`M^(+)+e^(-) to M` (Reduction)
`thereforeo X^(-)+M^(+) to X+M` Reaction will occur itself.