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What is emf of Daniell cell having 0.1 M...

What is emf of Daniell cell having 0.1 M `ZnSO_(4)` and 0.01 M `CuSO_(4)` solution ?
`[E_(Cu)^(o)=0.34V and E_(Zn)^(o)=-0.76V]`.

A

1.10V

B

1.04 V

C

1.16V

D

1.07V

Text Solution

Verified by Experts

The correct Answer is:
D

`E=E^(o)-(0.059)/(2)"log"([Zn^(2+)])/([Cu^(2+)])`
`E^(o)=E_((Cu^(2+)|Cu))^(o)-E_((Zn^(2+)|Zn))^(o)`
`E^(o)=0.34-(-0.76)`
`E^(o)=0.34+0.76`
`E^(o)=1.10V`
`E=1.10-(0.059)/(2)"log"(0.1)/(0.01)`
`=1.10-0.295=1.0705V`.
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Calculate the cell potential for Cu plate kept in 0.2 M CuSO_(4) solution. [E_(Cu^(+)|Cu^(2+))^(Theta)=0.34V]

What is the potential of a half-cell consisting of zinc electrode in "0.01 M ZnSO_(4) solution 25^(@)C. E^(@) = 0.763 V.

Knowledge Check

  • Emf of given Daniell cell at 298 K is E_(1) . Zn|ZnSO_(4)(0.01M)||CuSO_(4(1.0M))|Cu . The emf changed to E_(2) when concentration of ZnSO_(4) solution is 1.0 M and CuSO_(4) solution is 0.01 M, then what is the relation between E_(1) and E_(2) ?

    A
    `E_(1) gt E_(2)`
    B
    `E_(1) lt E_(2)`
    C
    `E_(1)=E_(2)`
    D
    `E_(2)=0 ne E_(1)`
  • In which metal container, the aqueous solution of CuSO_(4) can be stored? E_(Cu^(2+)//Cu)^(@)= 0.34V E_(Fe//Fe^(2+))^(@)= 0.44V, E_(Al//Al^(3+))^(@)= 1.66 V E_(Ni//Ni^(2+))^(@)= 0.25V, E_(Ag^(+)//Ag)^(@)= 0.80 V

    A
    Ag
    B
    Ni
    C
    Fe
    D
    Al
  • What is the pH of the resulting solution when equal volumes of 0.1 M NaOH and 0.01 M HCl are mixed ?

    A
    `7.0`
    B
    `1.04`
    C
    `12.65`
    D
    `2.0`
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    The standard emf for the cell cell reaction Zn + Cu^(2+) rarr Zn^(2+) + Cu is 1.10 volt at 25^@ C . The emf for the cell reaction when 0.1 M Cu^(2+) and 0.1 M ZN^(2+) solutions are used at 25^@ =C is .

    Calculate the EMF of a Daniel cell when the concentartion of ZnSO_(4) and CuSO_(4) are 0.001M and 0.1M respectively. The standard potential of the cell is 1.1V .

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    Which of the following is true for construct cell by E_(Cu^(2+)|Cu)^(Theta)=+0.34V and E_(H^(+)|H_(2))^(Theta)=0 ?