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After adding non-volatile solute freezin...

After adding non-volatile solute freezing point of water decreases to -`0.186^@C`. Calculate `DeltaT_b` if `K_f = 1.86 K kg mol^(-1)`and `K_b = 0.521 K kg mol^(-1)`

A

0.0186

B

1.86

C

0.0521

D

0.521

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaT_f = T_f^@ - T_f =0 -(-0.186^@) = 0.186^@C`
`DeltaT_f = K_f xxm`
`rArr m = (DeltaT_f)/(K_f) = 0.186/1.86 = 0.1 m`
`:. DeltaT_b = K_b xx m =0.521 xx 0.1 = 0.0521 K`
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Knowledge Check

  • After adding non-volatile solute freezing point of water decreases to -0.186^@C . Calculate Delta T_b if K_f=1.86K kg mol^(-1) and K_b=0.521 K kg mol^(-1) .

    A
    0.0521
    B
    0.0186
    C
    0.521
    D
    1.86

  • After adding non volatile solute freezing point of water decreases to -0.186^@C . calculate DeltaT_b if k_f=1.86 K kg mol^(-1) and k_b=0.521 L kg mol^(-1)

    A
    0.0521
    B
    0.0186
    C
    0.521
    D
    1.86

  • After adding non-volatile solute freezing point of water decreases to -0.186^(@)C . Calculate Delta T_(b) if K_(f)=1.86 " K kg mol"^(-1) and K_(b)=0.21 "K kg mol"^(-1) .

    A
    1.86
    B
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    C
    0.0186
    D
    0.0521

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