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Find the locus of the points of trisecti...

Find the locus of the points of trisection of double ordinate of a parabola `y^(2)=4ax (agt0)`

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The correct Answer is:
`9y^(2) = 4 ax`
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Knowledge Check

  • The locus of the points of intersection of perpendicular normals of the parabola y^2=4ax is

    A
    `y^2-2ax+a^2=0`
    B
    `y^2-ax+2a^2=0`
    C
    `y^2-ax+2a^2=0`
    D
    `y^2-ax+3a^2=0`
  • The equation of the locus of the point of intersection of two normals to the parabola y^(2)=4ax which are perpendicular to each other is

    A
    `y^(2)=a(x-3a)`
    B
    `y^(2)=a(x+3a)`
    C
    `y^(2)=a(x+2a)`
    D
    `y^(2)=a(x-2a)`
  • The locus of the point of intersection of two tangents to the parabola y^(2)=4ax which make the angles theta_(1) and theta_(2) with the axis so that tan^(2) theta_(1) tan^(2) theta_(2) =k is

    A
    kx-y=0
    B
    kx-a=0
    C
    y=ka=0
    D
    `kx^(2)+2ax-y^(2)=0`
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    The locus of the point of intersection of two tangents to the parabola y^(2)=4ax which make complementary angles with the axis of the parabola is

    Prove that the locus of point of intersection of two perpendicular normals to the parabola y^(2) = 4ax is the parabola y^(2) = a(x-3a) .

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