Home
Class 12
MATHS
Find the equation of the parabola whose ...

Find the equation of the parabola whose focus is (-2,3) and directrix is the line 2x+3y-4=0. Also find the length of the latus rectum and the equation of the axis of the parabola.

Text Solution

Verified by Experts

The correct Answer is:
`9x^(2) - 12xy + 4y^(2) + 68x - 54y + 153 =0`, length of the latus rectum `= (2)/(sqrt13)` Equation of the axis of the parabola is `3x - 2y + 12=0`
Promotional Banner

Topper's Solved these Questions

  • PARABOLA

    AAKASH SERIES|Exercise EXERCISE -3.2 I.|6 Videos

  • PARABOLA

    AAKASH SERIES|Exercise EXERCISE -3.2 II.|7 Videos

  • PARABOLA

    AAKASH SERIES|Exercise EXERCISE -3.1 II.|5 Videos

  • MEASURES OF DISPERSION (STATISTICS)

    AAKASH SERIES|Exercise Practice Exercise|54 Videos

  • PARTIAL FRACTIONS

    AAKASH SERIES|Exercise PRACTICE EXERCISE|31 Videos

Similar Questions

Explore conceptually related problems

Find the equation of the parabola with focus (2,0) and directrix x=-2 .

Find the equation of parabola whose focus is (-3,0) and directrix is x + 5 = 0

Find the equation of parabola whose focus is (-2,3) and the directrix is 2x+3y=4

Find the equation of parabola whose focus is (0, 4) and directrix is y + 4 = 0

Equation of parabola whose focus is (0, 4) and directrix is y + 4 = 0 is

The equation of the parabola with focus (1,-1) and directrix x+y+3=0 is

The equation or the parabola with focus (0, 0) and directrix x+y = 4 is