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Find the image of the interval [1,3] und...

Find the image of the interval [1,3] under the mapping `f: R to R` given:
`f(x) = 2x^(3)-24x + 107`

Text Solution

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The correct Answer is:
[75, 89]
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Find the intervals in which the function f given by f(x) = 2x^(3) – 3x^(2) – 36x + 7 is (a) increasing (b) decreasing

Find the maximum value of 2x^(3) – 24x + 107 in the interval [1, 3]. Find the maximum value of the same function in [–3, –1].

Knowledge Check

  • If f: R to R defined by f(x) =x^(2)-2x-3 , then f is:

    A
    a function
    B
    one one
    C
    onto
    D
    one one onto
  • If f : R to R be given by f (x) = (3 -x ^(3)) ^(1/3), then fof (x) is

    A
    `x ^(1/3)`
    B
    `x ^(3)`
    C
    `x`
    D
    `(3-x ^(3)).`
  • f: R rarr R , f(x)=x^(3)-3x^(2)+6x-5 is

    A
    one-one and onto
    B
    one-one and into
    C
    onto but not one-one
    D
    neither one-one nor onto
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