A particle moved from position vec r(1) ...

A particle moved from position `vec r_(1) = 3 hati + 2 hatj - 6 hatk `to position `vecr_(2) = 14 hati + 13 hatj +9 hatk` undre the action of a force `(4 hati + hatj +3 hatk)` newtons . Find the work done .

100 J

50 J

200 J

75 J

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The correct Answer is:

`W = vec(F).(vec(r )_(2)-vec(r )_(1))=(4hat(i)+hat(j)+3hat(k))(11hat(i)+11hat(j)+15hat(k))`
`W=44+11+45=100` Joule.

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