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A particale moves under the effect of a ...

A particale moves under the effect of a force `F = Cs` from `x = 0` to `x = x_(1)`. The work down in the process is

A

`Cx_(1)^(2)`

B

`(1)/(2)Cx_(1)^(2)`

C

`Cx_(1)`

D

Zero

Text Solution

Verified by Experts

The correct Answer is:
B
`W int_(0)^(x_(1))F.dx=int_(0)^(x_(1))Cx dx =C[(x^(2))/(2)]_(0)^(x_(1))=(1)/(2)Cx_(1)^(2)`
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Knowledge Check

  • A particale moves under the effect of a force F = Cs from s = 0 to s = s_(1) . The work down in the process is

    A
    `Cx_(1)^(2)`
    B
    `(1)/(2)Cx_(1)^(2)`
    C
    `Cx_(1)`
    D
    Zero

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    A
    `(1)/(2)Cx^(2)`
    B
    `Cx^(2)`
    C
    Cx
    D
    `(1)/(2) Cx`

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    A
    70 units
    B
    270 units
    C
    35 units
    D
    150 units

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