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Two electrons each are fixed at a distan...

Two electrons each are fixed at a distance '2d'. A third charge proton placed at the midpoint is displaced slightly by a distance `x (x lt lt d)` perpendicular to the line joining the two fixed charges. Proton will execute simple harmonic motion having angular frequency : (m = mass of charged particle)

A

`((2q^2)/(piepsilon_(0)md^3))^(1/2)`

B

`((piepsilon_(0)md^3)/(2q^2))^(1/2)`

C

`((q^2)/(2piepsilon_(0)md^3))^(1/2)`

D

`((2piepsilon_(0)md^3)/(q^2))^(1/2)`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • Two masses of mass m each are fixed at a separation distance of 2d . A small mass m_(s) placed midway, when displaced slightly, starts oscillating. Then :

    A
    Frequency of simple harmonic motion is given by `1/(2pi)sqrt((4Gm)/(d^(3)))`
    B
    Frequency of simple harmonic motion is given by `1/(2pi)sqrt((2Gm)/(d^(3)))`
    C
    Accleration of the mass `m_(s)`, is given by `(Gm)/(d^(2))`
    D
    Time period of vibration is `2pisqrt((GM)/((2d)^(3))`

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    A
    `x=(d)/(sqrt(2))`
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  • Two point charges +9e and +e are kept at a distance 'a' from each other. A third charge is placed at a distance 'x' from +9e on the line joining the above two charges. For the third charge to be in equilibrium 'x' is

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