The normal reaction 'N' for a vehicle of 800 kg mass, negotiating a turn on a `30^(@)` banked road at maximum possible speed without skidding is _______ `xx 10^(3)" kg m/s"^(2)`.

The coefficient of friction between the tyres and the road is 0.25. The maximum speed with which a car can be driven round a curve of radius 40 m without skidding is (assume g = 10 ms^(-2) )

The coefficient of friction between the tyres and the road is 0.1. The maximum speed with which a cyclist can take a circular turn of radius 3 m without skidding is ("Take g"=10ms^(-2))

A turn of radius 600 m is banked for a vehicle of mass 200 kg going with a speed of 180kmh^(-1) . Determine the banking angle of its path.

A ring of mass 1kg and diameter 1m is rolling on a plane road with a speed 2m/s. Its kinetic energy would be -

A turn of radius 100 m is banked for a speed of 20 m/s (a) Find the banking angle (b) If a vehicle of mass 500 kg negotiates the curve find the force of friction on it if its speed is – (i) 30 m/s (ii) 10 m/s Assume that friction is sufficient to prevent skidding and slipping. [Take "tan" 22^(@) = 0.4 , "sin" 22^(@) = 0.375 , "cos" 22^(@) = 0.93 , g = 10 ms^(-2) ]

A vehicle is travelling along concave road then along convex road of same radius of curvatures at uniform speed. If the normal reactions on the vehicle as it crosses the lowest point of concave surface, highest point of concave surface, highest point of convex surface are 1.5 xx 10^(4) N, 3 xx 10^(3) N respectively, then the mass of vehicle is (g = 10 m//s^(-2)) .

Calculate the speed of Jupiter if the mass of Jupiter is 1.9 xx 10^(27) kg . Distance from the sun is 7.8 xx 10^(11)m and the mass of the sun is 2 xx 10^(30) kg .

The radius of curbature of a road is 60 m. if the angle of banking is 27^(@) find the maximum speed with which a vehicle can turn safely along this curve.