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A point P lies on the circle x^(2)+y^(2)...

A point P lies on the circle `x^(2)+y^(2)=169`. If `Q=(5,12)` and `R=(-12,5)`, then the angle `angle QPR` is

A

`(pi)/(6)`

B

`(pi)/(4)`

C

`(pi)/(3)`

D

`(pi)/(2)`

Text Solution

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Knowledge Check

  • A point P lies on the circle x^(2) + y^(2) = 169 . If Q = (5 , 12) and R = (-12 , 5) , then the angle angleQPR is _

    A
    `(pi)/(6)`
    B
    `(pi)/(4)`
    C
    `(pi)/(3)`
    D
    `(pi)/(2)`

  • A point P lines on the circle x^2+y^2=169 . If Q = (5, 12) and R= (-12, 5) , then angle angleQPR is

    A
    `pi/6`
    B
    `pi/4`
    C
    `pi/3`
    D
    `pi/2`

  • If theta is the acute angle of intersection at a real point of intersection of the circle x^(2) + y^(2) =5 and the parabola y^(2)=4x , then the value of tan theta is-

    A
    1
    B
    `sqrt(3)`
    C
    `(1)/(sqrt(3))`
    D
    3

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