Home
Class 11
PHYSICS
Determine the heat energy required to me...

Determine the heat energy required to melt 5 kg of ice completely at 0°C.Latent heat of fusion of water is `3336×10^3JKg^-1`

Answer

Step by step text solution for Determine the heat energy required to melt 5 kg of ice completely at 0°C.Latent heat of fusion of water is 3336×10^3JKg^-1 by PHYSICS experts to help you in doubts & scoring excellent marks in Class 11 exams.

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • THERMODYNAMICS

    MAXIMUM PUBLICATION|Exercise EXERCISE|85 Videos
  • THERMAL PROPERTIES OF MATTER

    MAXIMUM PUBLICATION|Exercise EXERCISE|56 Videos
  • UNITS AND MEASUREMENTS

    MAXIMUM PUBLICATION|Exercise EXERCISE|113 Videos

Similar Questions

Explore conceptually related problems

Calculate the entropy change in the melting of 1kg of ice at 0^(@)C. Heat of fusion of ice = 334.72 Jg^(-1).

Clculate the entropy change in the melting of 1 kg of ice at 0^(@)C. Heat of fusion of ice =334.72 J g ^(-1).

Knowledge Check

  • A bullet of mass 50 g and specific heat capacity 800" J kg"^(-1)K^(-1) is initially at a temperature 20^(@)C . It is fire vertically upwards with a speed of 200" ms"^(-1) and on returning to the starting point strikes a lump of ice at 0^(@)C and gets embedded in it. Assume that all the energy of the bullet is used up in melting. Neglect the friction of air Latent heat of fusion of ice = 3.36 xx 10^(5)" Jkg"^(-1) .

    A
    Energy of bullet used in melting is 1000 J
    B
    The mass of ice melted = 5g
    C
    The mass of ice melted is slightly greater than 5 g
    D
    The mass of ice melted is less than 5 g
  • A 10 H inductor carries a current of 20A. How much ice at 0^(@)C could be melted by the energy stored in the magnetic field of the inductor? Latent heat of ice is 22.6xx10^(3)J//kg

    A
    0.088kg
    B
    0.066kg
    C
    0.044kg
    D
    0.022kg
  • A copper block of mass 2.5 kg is heated in furnace to a temperature of 500^(@)C and then placed on a large ice block. What is the maximum amount of ice that can melt? (Specific heat of copper = 0.39 J/g-K, heat of fusion of water = 335 J/g)

    A
    2.5 kg
    B
    1.5 kg
    C
    4 kg
    D
    3 kg
  • Similar Questions

    Explore conceptually related problems

    A copper block of mass 2.5kg is heated in a furnace to a temperature of 500°C and then placed on a large ice block. What is the maximum amount of ice that can melt?(Specific heat of copper = 0.39Jg^-1 K^-1 , latent heat of fusion of water = 335Jg^-1) .

    Calculate the increase in internal energy of 1 kg of water at 100^(@)C when it is converted into steam at the sa temperature and at 1 atm (100 kPa). The density of water and steam are 1000 kg m and 0.6 kg respectively. The latent heat of vapourisation of water =2.25 xx 10 ^(6) J kg ^(-1)

    A nice box used for keeping eatables has a total wall area of 1 m^(2) and a wall thickness of 5.0 cm. the thermal conductivity of the ice box is K = 0.01" joule/metre-"^(@)C . It is filled with ice at 0^(@)C along with eatables on a day when the temperature is 30^(@)C . The latent heat of fusion of ice is 334 xx 10^(3)" joule/kg" . The amount of ice melted in one day is (1 day=86.400 s)

    A 2 kg copper block is heated to 500^(@)C and then it is placed on a large block of ice at 0^(@)C . If the specific heat capacity of copper is "400 J/kg"-^(@)C and latent heat of fusion of water is 3.5 xx 10^(5)" J/kg" the amount of ice that can melt is:

    A 2 kg copper block is heated to 500^(@)C and then it is placed on a large block of ice at 0^(@)C . If the specific heat capacity of copper is 400" J "kg^(-1)""^(@)C^(-1) and latent heat of fusion of watter is 3.5 times 10^(5)" J "kg^(-1) , the amount of ice that can melt is :