Home
Class 12
CHEMISTRY
(a) Explain the following terms: (i) R...

(a) Explain the following terms:
(i) Rate of a reaction. (ii) Activation energy of a reaction.
(b)The decomposition of phosphine, `PH_(3)` proceeds according to the following equation:
Rate `=k[PH_(3)]`
The half-life of `PH_(3)` is 37.9 s at `120^(@)C`.
(i) How much time is required for `3//4th` of `PH_(3)` to decompose?
(ii) What fraction of the original sample of `PH_(3)` remains behind after 1 minute?

Text Solution

Verified by Experts

The correct Answer is:
(i) 75.83s, (ii) 0.3342
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CHEMICAL KINETICS

    U-LIKE SERIES|Exercise SELF ASSESSMENT TEST (SECTION C)|1 Videos

  • CBSE EXAMINATION PAPER 2020 (CODE No.56/4/1)

    U-LIKE SERIES|Exercise SECTION -D|3 Videos

  • CHEMISTRY IN EVERYDAY LIFE

    U-LIKE SERIES|Exercise LONG ANSWER QUESTIONS - I|21 Videos

Similar Questions

Explore conceptually related problems

The decomposition of phosphine, PH_(3) , proceeds according to the following equation: 4PH_(3)(g) to P_(4)(g) +6H_(2)(g) It is found that the reaction follows the following rate equation: Rate =k[PH_(3)] . The half-life of PH_(3) is 37.9s at 120^(@)C . (i) How much time is required for 3//4th of PH_(3) to decompose? (ii) What fraction of the original sample of PH_(3) remains behind after 1 minute?

(a) Explain the following terms : (i) Rate of a reaction. (ii) Activation energy of a reaction. (b) The decomposition of phosphine, PH_(3) , proceeds according to the following equation : 4" PH"_(3)(g)to P_(4)(g)+6" H"_(2)(g) It is found that the reaction follows the following rate equation : Rate =k[PH_(3)] The half-life of PH_(3) is 37.9 s at 120^(@)C . (i) How much time is required for 3//4th of PH_(3) to decompose. (ii) What fractional of the original sample of PH_(3) remains behind after 1 minute ?

Knowledge Check

  • The decomposition of phosphine (PH_(3)) on tungsten at low pressure is a first-orfer reaction . It is because the

    A
    Rate of decomposition is very slow
    B
    Rate is proportional to the surface coverage
    C
    Rate is inversely proportional to the surface coverage
    D
    Rate is independent of the surface coverage

  • The decomposition of phosphine (PH_3) on tangents at low pressure is a first-order reaction. It is because the:

    A
    Rate is proportional to the surface coverage
    B
    Rate is inversely proportional to the surface coverage
    C
    Rate is independent of the surface coverage
    D
    Rate of decomposition is very low

  • The decomposition of phosphine (PH_3) on tangents at low pressure is a first-order reaction. It is because the:

    A
    Rate is proportional to the surface coverage
    B
    Rate is inversely proportional to the surface coverage
    C
    Rate is independent of the surface coverage
    D
    Rate of decomposition is very low

    • Similar Questions

    Explore conceptually related problems

    (a) Explain the following terms : (i) Rate of a reaction (ii) Activation energy of a reaction (b) The decompositon of phosphine , PH3, proceeds according to the following equation : 4 PH_(3) (g) to P_(4)(g) + 6 H_(2) (g) It is found that the reaction follows the following rate equation : Rate = k [ PH_(3)] . The half-life of PH_(3)" is "37.9" s at "120^(@)C . (i) How much time is required for 3//4^("th") "of " PH_(3) to decompose ? (ii) What fraction of the original sample of PH_(3) remains behind after 1 minute ?

    Decomposition of phosphine (PH_(3)) at 120^(@) C proceeds according to the equation 4PH_(3)(g) to P_(4)(g) + 6H_(2)(g) It was found that the reactioin follows the rate equation, Rate = k[PH_(3)] The half life period of PH_(3) is 37.9 s at 120^(@) C. i) How much time will be required for 3//4 of PH_(3) to decompose? ltrbgt ii) What function of the original amount of PH_(3) will remain undecomposed after 1 minute?

    PH_(3) can be obtained by:

    The decomposition of phosphine [PH_(3)] on tungsten at low pressure is a first-order reaction. It is because the

    PH_(3) is purified by

    Home
    Profile