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The maximum range of projectile fired wi...

The maximum range of projectile fired with some initial velocity is found to be 1000 m, in the absence of wind and air resisstance. The maximum height reached by the projectile is

A

250 m

B

500 m

C

1000 m

D

2000 m

Text Solution

Verified by Experts

The correct Answer is:
A
Range , R = ` (u^(2) sin 2 theta)/(g)`
For maximum range, angle of projection ` theta " is" 45^(@)`
` R_(max)= (u^(2) sin (2 xx 45^(@))/g = u^(2)/g = 1000 m`
maximum height , ` H = ( u^(2) sin^(2) 45^(@))/( 2 g ) `
`H = 1/2 xx 1000 xx (1/sqrt2)^(2)= 250 m`
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