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The maximum range of projectile fired wi...

The maximum range of projectile fired with some initial velocity is found to be 1000 m, in the absence of wind and air resisstance. The maximum height reached by the projectile is

A

250 m

B

500 m

C

1000 m

D

2000 m

Text Solution

Verified by Experts

The correct Answer is:
A

Range , R = ` (u^(2) sin 2 theta)/(g)`
For maximum range, angle of projection ` theta " is" 45^(@)`
` R_(max)= (u^(2) sin (2 xx 45^(@))/g = u^(2)/g = 1000 m`
maximum height , ` H = ( u^(2) sin^(2) 45^(@))/( 2 g ) `
`H = 1/2 xx 1000 xx (1/sqrt2)^(2)= 250 m`
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Knowledge Check

  • The maximum range of a projecitle fired with some initial velocity is found to be 1000 metre The maximum height (H) reached by this projectile is:-

    A
    250 metre
    B
    500 metre
    C
    1000metre
    D
    2000metre
  • If the initial velocity of a projectile be doubled, keeping the angle of projection same, the maximum height reached by it will

    A
    Remain the same
    B
    Be doubled
    C
    Be quadrupled
    D
    Be halved
  • A projectile is thrown with an initial velocity of (a hati + hatj) ms^(-1) . If the range of the projectile is twice the maximum height reached by it, then

    A
    `a = 2b`
    B
    `b = a`
    C
    `b = 2a`
    D
    `b = 4a`
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