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((sin2A)/(secA-1))((sec2A)/(sec2A+1))=...

`((sin2A)/(secA-1))((sec2A)/(sec2A+1))=`

A

`"Tan"A/2`

B

`-"Tan"A/2`

C

`"cot"A/2`

D

`-"Tan"A/2`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • ((sin 2A)/(sec A -1))((sec 2A)/(sec 2A+1))=

    A
    `sin A//2 `
    B
    `cos A//2`
    C
    `tan A//2`
    D
    `cot A//2 `

  • intx ((sec 2x-1)/(sec 2x+1))dx=

    A
    ` x tan x-log|secx| (x^(2))/(2)+c`
    B
    `x tan x-log|sec x|- (x^(2))/(2)+c`
    C
    `x tan x+log|sec x|-(x^(2))/(2)+c`
    D
    `x tan x+log|sec x|(x^(2))/(2)+c`

  • If (sin^(-1)a)^(2)+(cos^(-1)b)^(2)+(sec^(-1)c)^(2)+(cosec^(-1)d)^(2)=(5pi)^(2)/2 , then the value of (sin^(-1)a)^(2)-(cos^(-1)b)^(2)+(sec^(-1)c)^(2)-(cosec^(-1)d)^(2) is equal to

    A
    `-pi^(2)`
    B
    `-pi^(2)/2`
    C
    0
    D
    `pi^(2)/2`

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    sec^(-1)((2sqrt(2))/(1+sqrt(3)))=

    sec h^(-1) ((1)/(sqrt(2))) =

    cosec^(2)Acot^(2)A-sec^(2)Atan^(2)A-(cot^(2)A-tan^(2))(sec^(2)Acosec^(2)A-1) =

    underset(x to 0)"Lt" (sec x-1)/(x^(2)(sec x+1)^(2))=

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