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Two blocks ( m = 0.5 kg and M = 4.5 kg) ...

Two blocks ( m = 0.5 kg and M = 4.5 kg) are arranged on a horizontal frictionless table as shown in figure. The coefficient of static friction between the two blocks is `(3)/( 7)`. Then the maximum horizontal force that can be applied on the larger block move together is `"_____________"` N. ( Round off to the Nearest Integer ) [Take as `9.8 ms^(-2)` ]

Answer

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Knowledge Check

  • Coefficient of static friction between the two blocks in Fig. 7.124 is mu and the table is frictionless . Maximum horizontal force which can be applied on the lower such that the blocks move together , is :

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