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An object is displaced from position vec...

An object is displaced from position vector `r_1=(2hati+3hatj)` m to `r_2=(4hati+6hatj)` m under a force `F=(3x^2hati+2yhatj)N` Find the work done by this force.

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To find the work done by the force \( F = (3x^2 \hat{i} + 2y \hat{j}) \) when an object is displaced from position vector \( \mathbf{r_1} = (2 \hat{i} + 3 \hat{j}) \) m to \( \mathbf{r_2} = (4 \hat{i} + 6 \hat{j}) \) m, we can follow these steps: ### Step 1: Define the displacement vector The displacement vector \( \mathbf{dr} \) can be defined as: \[ \mathbf{dr} = d\mathbf{r} = dx \hat{i} + dy \hat{j} \] ### Step 2: Write the work done formula The work done \( W \) by the force during the displacement from \( \mathbf{r_1} \) to \( \mathbf{r_2} \) is given by the line integral: \[ W = \int_{\mathbf{r_1}}^{\mathbf{r_2}} \mathbf{F} \cdot d\mathbf{r} \] Substituting the expressions for \( \mathbf{F} \) and \( d\mathbf{r} \): \[ W = \int_{\mathbf{r_1}}^{\mathbf{r_2}} (3x^2 \hat{i} + 2y \hat{j}) \cdot (dx \hat{i} + dy \hat{j}) \] ### Step 3: Calculate the dot product Calculating the dot product: \[ \mathbf{F} \cdot d\mathbf{r} = (3x^2 \hat{i} + 2y \hat{j}) \cdot (dx \hat{i} + dy \hat{j}) = 3x^2 dx + 2y dy \] Thus, the work done becomes: \[ W = \int_{\mathbf{r_1}}^{\mathbf{r_2}} (3x^2 dx + 2y dy) \] ### Step 4: Set up the limits of integration The limits of integration for \( x \) will be from \( x_1 = 2 \) to \( x_2 = 4 \), and for \( y \) from \( y_1 = 3 \) to \( y_2 = 6 \). ### Step 5: Integrate with respect to \( x \) and \( y \) We can separate the integral: \[ W = \int_{2}^{4} 3x^2 dx + \int_{3}^{6} 2y dy \] Calculating the first integral: \[ \int 3x^2 dx = x^3 \quad \text{(from 2 to 4)} \] Evaluating: \[ [4^3 - 2^3] = [64 - 8] = 56 \] Calculating the second integral: \[ \int 2y dy = y^2 \quad \text{(from 3 to 6)} \] Evaluating: \[ [6^2 - 3^2] = [36 - 9] = 27 \] ### Step 6: Add the results of the integrals Combining both results: \[ W = 56 + 27 = 83 \text{ Joules} \] ### Final Answer The work done by the force is \( W = 83 \) Joules. ---

To find the work done by the force \( F = (3x^2 \hat{i} + 2y \hat{j}) \) when an object is displaced from position vector \( \mathbf{r_1} = (2 \hat{i} + 3 \hat{j}) \) m to \( \mathbf{r_2} = (4 \hat{i} + 6 \hat{j}) \) m, we can follow these steps: ### Step 1: Define the displacement vector The displacement vector \( \mathbf{dr} \) can be defined as: \[ \mathbf{dr} = d\mathbf{r} = dx \hat{i} + dy \hat{j} \] ...
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