A projectile is fired from a gun at an angle of `45^@` with the horizontal and with a speed of `20m//s` relative to ground. At the highest point in its flight the projectile explodes into two fragments of equal masses. One fragement, whose initial speed is zero falls vertically. How far from the gun does the other fragment land, assuming a level terrain? Take `g=10m//s^2`?

Explanation

To solve the problem step by step, we will follow these instructions:

### Step 1: Understand the projectile motion
A projectile is fired at an angle of \(45^\circ\) with an initial speed of \(20 \, \text{m/s}\). We need to find the range of the projectile before it explodes.

### Step 2: Calculate the range of the projectile
The range \(R\) of a projectile launched at an angle \(\theta\) with an initial speed \(u\) is given by the formula:
\[
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