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A block in SHM starts from + A position....

A block in SHM starts from `+ A` position. Write `S - t` equation of the block, if `S` is measured from `-A`.

A

`S = A(1 + cos omega t)`

B

`S =2 A(1 + cos omega t)`

C

`S = A(cos omega t)`

D

`S = A(1 + 2cos omega t)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the \( S - t \) equation of a block in Simple Harmonic Motion (SHM) that starts from the position \( +A \), with \( S \) measured from \( -A \), we can follow these steps: ### Step 1: Understand the Initial Position The block starts at position \( +A \) at time \( t = 0 \). In SHM, the position \( x \) of the block can be described by the equation: \[ x(t) = A \cos(\omega t) \] where \( A \) is the amplitude and \( \omega \) is the angular frequency. ### Step 2: Define the New Reference Point Since \( S \) is measured from \( -A \), we need to relate \( S \) to the position \( x \). The distance \( S \) from \( -A \) to the block's position \( x \) can be expressed as: \[ S = x + A \] This is because when the block is at \( -A \), \( S \) will be zero. ### Step 3: Substitute the Position Equation Now, substitute the expression for \( x(t) \) into the equation for \( S \): \[ S = (A \cos(\omega t)) + A \] ### Step 4: Simplify the Expression Combine the terms: \[ S = A + A \cos(\omega t) \] Factoring out \( A \): \[ S = A(1 + \cos(\omega t)) \] ### Final Equation Thus, the equation relating \( S \) and \( t \) is: \[ S(t) = A(1 + \cos(\omega t)) \]

To find the \( S - t \) equation of a block in Simple Harmonic Motion (SHM) that starts from the position \( +A \), with \( S \) measured from \( -A \), we can follow these steps: ### Step 1: Understand the Initial Position The block starts at position \( +A \) at time \( t = 0 \). In SHM, the position \( x \) of the block can be described by the equation: \[ x(t) = A \cos(\omega t) \] where \( A \) is the amplitude and \( \omega \) is the angular frequency. ...
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