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A block of wood floats in a bucket of wa...

A block of wood floats in a bucket of water placed in a lift. Will the block sink more or less if the lift starts accelerating up?

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To determine whether a block of wood will sink more or less when a lift starts accelerating upwards, we can analyze the forces acting on the block in both stationary and accelerating conditions. ### Step-by-Step Solution: 1. **Understand the Initial Conditions**: - The block of wood is floating in water inside a stationary lift. - The buoyant force (upward force) acting on the block is equal to the weight of the water displaced by the submerged part of the block. 2. **Identify Forces Acting on the Block**: - The forces acting on the block are: - Weight of the block (downward): \( W = mg \) - Buoyant force (upward): \( F_B = \rho_L \cdot V_s \cdot g \) - Where \( \rho_L \) is the density of the liquid (water), \( V_s \) is the volume of the block submerged in water, and \( g \) is the acceleration due to gravity. 3. **Condition When Lift is Stationary**: - In a stationary lift, the buoyant force equals the weight of the block: \[ F_B = W \implies \rho_L \cdot V_s \cdot g = mg \] - The volume submerged can be expressed as: \[ V_s = \frac{m}{\rho_L} \] 4. **Condition When Lift Accelerates Upwards**: - When the lift accelerates upwards with acceleration \( a \), the effective gravitational force on the block changes to \( g' = g + a \). - The new buoyant force is: \[ F_B' = \rho_L \cdot V_s' \cdot (g + a) \] - The weight of the block remains the same: \[ W = mg \] 5. **Apply Newton's Second Law**: - The net force acting on the block when the lift accelerates upwards is given by: \[ F_B' - mg = ma \] - Rearranging gives: \[ F_B' = mg + ma = m(g + a) \] 6. **Equating Buoyant Forces**: - Setting the buoyant force equal to the new effective weight: \[ \rho_L \cdot V_s' \cdot (g + a) = m(g + a) \] - This implies: \[ V_s' = \frac{m}{\rho_L} \] 7. **Conclusion**: - Since \( V_s' = V_s \), the volume of the block submerged does not change when the lift accelerates upwards. Thus, the block will neither sink more nor less; it will maintain its position. ### Final Answer: The block of wood will neither sink more nor less when the lift starts accelerating upwards; it will maintain its position.

To determine whether a block of wood will sink more or less when a lift starts accelerating upwards, we can analyze the forces acting on the block in both stationary and accelerating conditions. ### Step-by-Step Solution: 1. **Understand the Initial Conditions**: - The block of wood is floating in water inside a stationary lift. - The buoyant force (upward force) acting on the block is equal to the weight of the water displaced by the submerged part of the block. ...
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