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In the figure shown V(ab) at t=1 is...

In the figure shown `V_(ab)` at `t=1` is

A

`30V`

B

`-30V`

C

`20V`

D

`-20V`

Text Solution

Verified by Experts

The correct Answer is:
B
`i=(dq)/(dt)=(8t)A`
`(di)/(dt)=8A//s`
At `t=1s, q=4C,i=8A`
and `(di)/(dt)=8A//s`
Change on capacitor is increasing. So charge on positive plate is also increasing. Hence direction of current is towards left.

Now, `V_a+2xx8-4+2xx8+4/2=V_b`
`:. V_a-V_b=-30V`
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