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A particle is moving in a circle of radi...

A particle is moving in a circle of radius R with constant speed. The time period of the particle is T. In a time `t=(T)/(6)`
Average speed of the particle is ……

A

`(pi R)/(6T)`

B

`(2pi R)/(3T)`

C

`(2 pi R)/(T)`

D

`(R)/(T)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will find the average speed of a particle moving in a circular path with a given radius and time period. ### Step-by-Step Solution: 1. **Understand the given parameters**: - The radius of the circular path is \( R \). - The time period of the particle is \( T \). - The time interval we are considering is \( t = \frac{T}{6} \). 2. **Identify the formula for average speed**: - The average speed \( v_{avg} \) is defined as: \[ v_{avg} = \frac{\text{Total Distance}}{\text{Total Time}} \] 3. **Calculate the distance traveled in time \( t \)**: - The distance traveled by the particle in time \( t \) can be calculated using the formula: \[ \text{Distance} = \text{Velocity} \times \text{Time} \] - Since the particle is moving with constant speed, let the speed be \( v \). Therefore, the distance traveled in time \( t \) is: \[ \text{Distance} = v \times t = v \times \frac{T}{6} \] 4. **Determine the time taken**: - The time taken to cover this distance is simply \( t = \frac{T}{6} \). 5. **Substitute into the average speed formula**: - Now, substituting the distance and time into the average speed formula: \[ v_{avg} = \frac{v \times \frac{T}{6}}{\frac{T}{6}} \] - The \( \frac{T}{6} \) terms cancel out: \[ v_{avg} = v \] 6. **Relate speed \( v \) to the radius and time period**: - The speed \( v \) can be expressed in terms of the radius \( R \) and the time period \( T \): \[ v = \frac{2\pi R}{T} \] - This is because the distance traveled in one complete revolution (circumference of the circle) is \( 2\pi R \), and it takes time \( T \) to complete that distance. 7. **Final expression for average speed**: - Therefore, substituting this back, we find: \[ v_{avg} = \frac{2\pi R}{T} \] ### Conclusion: The average speed of the particle in the time \( t = \frac{T}{6} \) is: \[ \boxed{\frac{2\pi R}{T}} \]
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