Home
Class 11
PHYSICS
A black body is at a temperature of 5760...

A black body is at a temperature of `5760 K`. The energy of radiation emitted by the body at wavelength `250 nm` is `U_(1)` at wavelength `500 nm` is `U_(2)` and that at `1000 nm` is `U_(3)`. Wien's consant, `b = 2.88 xx 10^(6) nmK`. Which of the following is correct?

A

`U_(3)` = 0

B

`U_(1)gtU_(2)`

C

`U_(2)gtU_(1)`

D

`U_(1) = 0`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will use Wien's law and the properties of black body radiation. ### Step-by-Step Solution: 1. **Understand Wien's Law**: Wien's law states that the wavelength at which the emission of a black body spectrum is maximized (λm) is inversely proportional to the temperature (T) of the body. The relationship is given by: \[ \lambda_m \cdot T = b \] where \( b \) is Wien's constant. 2. **Given Values**: - Temperature \( T = 5760 \, K \) - Wien's constant \( b = 2.88 \times 10^6 \, nm \cdot K \) 3. **Calculate λm**: To find the wavelength at which the maximum energy is emitted, we rearrange the formula: \[ \lambda_m = \frac{b}{T} \] Substituting the given values: \[ \lambda_m = \frac{2.88 \times 10^6 \, nm \cdot K}{5760 \, K} \] Performing the calculation: \[ \lambda_m \approx 500 \, nm \] 4. **Identify Energy Emission**: The problem states that: - \( U_1 \) is the energy emitted at \( 250 \, nm \) - \( U_2 \) is the energy emitted at \( 500 \, nm \) - \( U_3 \) is the energy emitted at \( 1000 \, nm \) According to the properties of black body radiation: - The energy emitted at the peak wavelength (which is \( U_2 \) at \( 500 \, nm \)) will be the maximum. - Energy decreases as we move away from the peak wavelength. 5. **Comparison of Energies**: Since \( 500 \, nm \) is the wavelength of maximum emission: \[ U_2 > U_1 \quad \text{and} \quad U_2 > U_3 \] Therefore, we can conclude: \[ U_2 > U_1 > U_3 \] 6. **Conclusion**: Based on the analysis, the correct relationship among the energies is: - \( U_2 \) is the maximum energy, - \( U_1 \) is greater than \( U_3 \), - \( U_3 \) is the least. ### Final Answer: The correct option is that \( U_2 > U_1 > U_3 \). ---

To solve the problem, we will use Wien's law and the properties of black body radiation. ### Step-by-Step Solution: 1. **Understand Wien's Law**: Wien's law states that the wavelength at which the emission of a black body spectrum is maximized (λm) is inversely proportional to the temperature (T) of the body. The relationship is given by: \[ \lambda_m \cdot T = b ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CALORIMETRY AND HEAT TRANSFER

    DC PANDEY ENGLISH|Exercise Match the columns|4 Videos
  • CALORIMETRY & HEAT TRANSFER

    DC PANDEY ENGLISH|Exercise Level 2 Subjective|14 Videos
  • CENTRE OF MASS

    DC PANDEY ENGLISH|Exercise Medical entrances gallery|27 Videos

Similar Questions

Explore conceptually related problems

A blackbody is at a temperature of 2880K. The energy of radiation emitted by this object with wavelength between 499nm and 500nm is U_1 , between 999nm and 1000nm is U_2 and between 1499 nm and 1500 nm is U_3 . The Wien constant b=2.88xx10^6nmK . Then

A black body is at a temperature of 2880 K. The energy of radiation emitted by this object with wavelength between 499 nm and 500 nm is U_(1) , between 999 nm and 1000 nm is U_(2) and between 1499 nm and 1500 nm is U_(3) . The Wein's constant b = 2.88 xx 10^(6) "nm K" . Then

Knowledge Check

  • Compare the energies of two radiations E_(1) with wavelength 800 nm and E_(2) with wavelength 400 nm.

    A
    `E_(1)=2E_(2)`
    B
    `E_(1)=E_(2)`
    C
    `E_(2)=2E_(1)`
    D
    `E_(2)=-1/2E_(1)`
  • Experimental investigations show that the intensity of solar radiation is maximum for a wavelength 480 nm in the visible ragion. Estimate the surface temperature of sun. (Given Wien's constant b = 2.88 xx 10^(-3) m K ).

    A
    `4000 K`
    B
    `6000 K`
    C
    `8000 K`
    D
    `10^(6) K`
  • Similar Questions

    Explore conceptually related problems

    Energy of radiation emitted by a black body at temperature 3000 K is u_(1) for wavelength between 8000 Å and 9000Å , u_(2) for wavelength between 9000 Å and 10000Å and u_(3) forwavelength between 10000Åand 11000Å .Which of the following is true? [Wien’s constant b=2.88xx10^(-3)mK]

    A black body, which is at a high temperature TK thermal radiation emitted at the rate of E W//m^(2) . If the temperature falls to T/4 K, the thermal radiation emitted in W//m^(2) will be

    Calculate the effective temperature of the sun . Given that the wavelength of maximum energy in the solar spectrum is 475 mm and Wien's constant is 2.898xx10^(-3) mK.

    Shown below are the black body radiation curves at temperature T_(1) and T_(2) (T_(2) gt T_(1)) . Which of the following plots is correct?

    A black body initially at 27^(@) C is heated to 327^(@) C. How many times is the total radiation emitted at the higher temperature than that emitted at the lower temperature ? What is the wavelength of the maximum energy radiation at the higher temperature ? Wien's constant = 2.898xx10^(-3) mK.

    The intensity of the solar radiation is maximum for wavelength lamda_(m)=4753Å in the visible region. The surface temepratureof the sun, is (Assume the sun to be a black body. Wien's constant (b) =2.892xx10^(-3)mK )