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Water is conveyed through a uniform tube...

Water is conveyed through a uniform tube of 8 cm in diameter and 3140 m in length at the rate `2 xx 10^(-3) m^(3)` per second. The pressure required to maintain the flow is ( viscosity of water =`10^(-3)` )

Text Solution

Verified by Experts

Here, 2r=8 cm =0.08 m or r=0.04 m, l=4 km =4000 m,
`V=20 "litre"//s=20xx10^(-3) m^(3)s^(-1), eta=0.001 Pa-s, p= ?`
As, `V=(pi p r^(4))/(8eta l) " or" p=(8V eta l)/(pi r^(4))`
`=(8xx(20xx10^(-3))xx0.001xx4000)/(((22)/(7))xx(0.04)^(4)) =7.954xx10^(4) Pa`
`therefore` Height of mercury column for pressure difference p will be,
`h=(p)/(rho g)=(7.954xx10^(4))/((13.6xx10^(3))xx9.8)=0.5968 m=59.68 cm`
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  • At What velocity does water emerge from an orifice in a tank in which gauge pressure is 3 xx 10^(5) Nm^(-2) before the flow starts ? (Take the density of water =1000 kg m^(-3) .)

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    C
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    D
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