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L, C and R represent the physical quanti...

L, C and R represent the physical quantities, inductance, capacitance and resistance respectively. The combination(s) which have the dimensions of frequency are

A

`(1)/(RC)`

B

`(R)/(L)`

C

`(1)/(sqrt(LC))`

D

`(C)/(L)`

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To determine which combinations of inductance (L), capacitance (C), and resistance (R) have the dimensions of frequency, we need to analyze the dimensions of each quantity and their combinations. ### Step-by-Step Solution: 1. **Understanding Dimensions of L, C, and R**: - Inductance (L) has the dimension: \([L] = [M^1 L^2 T^{-2} A^{-2}]\) - Capacitance (C) has the dimension: \([C] = [M^{-1} L^{-2} T^4 A^2]\) - Resistance (R) has the dimension: \([R] = [M^1 L^2 T^{-3} A^{-2}]\) 2. **Finding the Dimension of Frequency**: - Frequency (f) is defined as the reciprocal of the time period (T), hence its dimension is: \([f] = [T^{-1}]\). 3. **Analyzing the Combinations**: - **Combination 1: \( \frac{1}{CR} \)** - Calculate the dimension: \[ [CR] = [C][R] = [M^{-1} L^{-2} T^4 A^2] \cdot [M^1 L^2 T^{-3} A^{-2}] = [M^0 L^0 T^1 A^0] = [T] \] - Therefore, \( \frac{1}{CR} \) has the dimension: \[ \left[\frac{1}{CR}\right] = [T^{-1}] \] - This matches the dimension of frequency. - **Combination 2: \( \frac{L}{R} \)** - Calculate the dimension: \[ \frac{L}{R} = \frac{[L]}{[R]} = \frac{[M^1 L^2 T^{-2} A^{-2}]}{[M^1 L^2 T^{-3} A^{-2}]} = [T] \] - Therefore, \( \frac{L}{R} \) has the dimension: \[ \left[\frac{L}{R}\right] = [T] \] - Thus, \( \frac{1}{\frac{L}{R}} = \frac{R}{L} \) has the dimension: \[ [T^{-1}] \] - This also matches the dimension of frequency. - **Combination 3: \( \sqrt{CR \cdot LR} \)** - Calculate the dimension: \[ CR \cdot LR = [C][R][L][R] = [M^{-1} L^{-2} T^4 A^2] \cdot [M^1 L^2 T^{-3} A^{-2}] \cdot [M^1 L^2 T^{-2} A^{-2}] \] \[ = [M^{1-1} L^{2-2} T^{4-3-2} A^{2-2}] = [M^0 L^0 T^{-1} A^0] = [T^{-1}] \] - Therefore, \( \sqrt{CR \cdot LR} \) has the dimension: \[ [T^{-1}] \] - This matches the dimension of frequency. - **Combination 4: \( \frac{C}{L} \)** - Calculate the dimension: \[ \frac{C}{L} = \frac{[C]}{[L]} = \frac{[M^{-1} L^{-2} T^4 A^2]}{[M^1 L^2 T^{-2} A^{-2}]} = [M^{-2} L^{-4} T^6 A^4] \] - This does not match the dimension of frequency. 4. **Conclusion**: - The combinations that have the dimensions of frequency are: - \( \frac{1}{CR} \) - \( \frac{L}{R} \) - \( \sqrt{CR \cdot LR} \) ### Final Answer: The combinations that have the dimensions of frequency are: - \( \frac{1}{CR} \) - \( \frac{L}{R} \) - \( \sqrt{CR \cdot LR} \)

To determine which combinations of inductance (L), capacitance (C), and resistance (R) have the dimensions of frequency, we need to analyze the dimensions of each quantity and their combinations. ### Step-by-Step Solution: 1. **Understanding Dimensions of L, C, and R**: - Inductance (L) has the dimension: \([L] = [M^1 L^2 T^{-2} A^{-2}]\) - Capacitance (C) has the dimension: \([C] = [M^{-1} L^{-2} T^4 A^2]\) - Resistance (R) has the dimension: \([R] = [M^1 L^2 T^{-3} A^{-2}]\) ...
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