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A rectangular coil of 100 turns and size...

A rectangular coil of 100 turns and size `0.1mxx0.05m` is placed perpendicular to a magnetic field of 0.1 T. If the field drops to 0.05 T in 0.05 s, the magnitude of the emf induced in the coil is

A

`sqrt2`

B

`sqrt3`

C

`sqrt(0.6)`

D

0.5

Text Solution

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The correct Answer is:
To find the magnitude of the induced emf in the rectangular coil, we can follow these steps: ### Step 1: Identify the given parameters - Number of turns (N) = 100 - Size of the coil = 0.1 m x 0.05 m - Initial magnetic field (B_initial) = 0.1 T - Final magnetic field (B_final) = 0.05 T - Time interval (Δt) = 0.05 s ### Step 2: Calculate the area of the coil The area (A) of the rectangular coil can be calculated using the formula: \[ A = \text{length} \times \text{width} \] \[ A = 0.1 \, \text{m} \times 0.05 \, \text{m} = 0.005 \, \text{m}^2 \] ### Step 3: Calculate the change in magnetic flux The magnetic flux (Φ) through the coil is given by: \[ \Phi = B \times A \] The change in magnetic flux (ΔΦ) can be calculated as: \[ \Delta \Phi = \Phi_{\text{final}} - \Phi_{\text{initial}} \] Where: \[ \Phi_{\text{final}} = B_{\text{final}} \times A \] \[ \Phi_{\text{initial}} = B_{\text{initial}} \times A \] Calculating the initial and final flux: \[ \Phi_{\text{initial}} = 0.1 \, \text{T} \times 0.005 \, \text{m}^2 = 0.0005 \, \text{Wb} \] \[ \Phi_{\text{final}} = 0.05 \, \text{T} \times 0.005 \, \text{m}^2 = 0.00025 \, \text{Wb} \] Now, calculate the change in flux: \[ \Delta \Phi = 0.00025 \, \text{Wb} - 0.0005 \, \text{Wb} = -0.00025 \, \text{Wb} \] ### Step 4: Calculate the induced emf (ε) The induced emf (ε) can be calculated using Faraday's law of electromagnetic induction: \[ \varepsilon = -\frac{\Delta \Phi}{\Delta t} \] Substituting the values: \[ \varepsilon = -\frac{-0.00025 \, \text{Wb}}{0.05 \, \text{s}} \] \[ \varepsilon = \frac{0.00025 \, \text{Wb}}{0.05 \, \text{s}} = 0.005 \, \text{V} \] ### Step 5: Multiply by the number of turns Since the coil has 100 turns, the total induced emf is: \[ \varepsilon_{\text{total}} = N \times \varepsilon \] \[ \varepsilon_{\text{total}} = 100 \times 0.005 \, \text{V} = 0.5 \, \text{V} \] ### Final Answer The magnitude of the induced emf in the coil is **0.5 V**. ---

To find the magnitude of the induced emf in the rectangular coil, we can follow these steps: ### Step 1: Identify the given parameters - Number of turns (N) = 100 - Size of the coil = 0.1 m x 0.05 m - Initial magnetic field (B_initial) = 0.1 T - Final magnetic field (B_final) = 0.05 T - Time interval (Δt) = 0.05 s ...
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Knowledge Check

  • A circular coil of 25 turns and radius 12 cm is placed in a uniform magnetic field of 0.5 T normal to the plane of the coil. If the current in the coil is 6 A then total torque acting on the coil is

    A
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    B
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    C
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    D
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  • A circular coil of 25 turns and radius of 12 cm is placed in a uniform magnetic field of 0.5 T normal to the plane of coil. If the current in the coil is 5 A, then total torque experienced by the coil is

    A
    1.5Nm
    B
    2.5Nm
    C
    3.5Nm
    D
    zero
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