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In a Young's double slit experiment, D e...

In a Young's double slit experiment, D equals the distance of screen and d is the separation between the slits. The distance of the nearest point to the central maximum where the intensity is same as that due to a single slit is equal to

A

`(Dlambda)/d`

B

`(Dlambda)/(2d)`

C

`(Dlambda)/(3d)`

D

`(2Dlambda)/d`

Text Solution

Verified by Experts

The correct Answer is:
C
Intensity, `I=4I_(0)"cos"^(2)phi/2`
`because I=I_(0)`
`:. Phi=(2pi)/3=(2pi)/lambda. Deltax=(2pi)/lambda ((yd)/D)`
`:. Y=(lambdaD)/(3d)`
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