In Young's double slit experiment, match the following two coloums.
`{:(,"Column I",,"Column II"),("A","When width of one slit is slightly increased",,"p. maximum intensity will increase"),("B","When one slit is closed",,"q. maximum intensity will decrease"),("C","When both the sources are made incoherent",,"r. maximum intensity will remain same"),("D","When a glass slab is inserted in front of one of the slits",,"s. fringe pattern will displacement"):}`
Note Assume absorption from glass slab to be negligible

Explanation

To solve the problem of matching the two columns in Young's double slit experiment, we will analyze each option in Column I and determine the corresponding effect in Column II.

### Step-by-Step Solution:

1. **Option A: When width of one slit is slightly increased**
- When the width of one slit is increased, the intensity of light passing through that slit increases. This results in a higher maximum intensity in the interference pattern since the intensity from that slit contributes more to the overall intensity.
- **Match:** A → p (maximum intensity will increase)

2. **Option B: When one slit is closed**
- Closing one slit means that there is no light coming from that slit, effectively reducing the total intensity. The maximum intensity will then be equal to the intensity from the open slit only.
- **Match:** B → q (maximum intensity will decrease)

3. **Option C: When both the sources are made incoherent**
- If both sources are incoherent, they do not maintain a constant phase relationship. This means that the interference pattern will not form as it does with coherent sources. The intensity will simply add up without interference effects.
- **Match:** C → r (maximum intensity will remain the same)

4. **Option D: When a glass slab is inserted in front of one of the slits**
- Inserting a glass slab introduces a phase shift due to the difference in optical path length. This can affect the fringe pattern, but since the intensity from both slits remains unchanged (assuming negligible absorption), the maximum intensity remains the same.
- **Match:** D → s (fringe pattern will be displaced)

### Final Matching:
- A → p (maximum intensity will increase)
- B → q (maximum intensity will decrease)
- C → r (maximum intensity will remain the same)
- D → s (fringe pattern will be displaced)