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The magnitude of the vector 6 hat(i) - 2...

The magnitude of the vector `6 hat(i) - 2hat(j) + 3hat(k)` is a) 5 units b) 7 units c) 11 units d) 1 unit

A

5 units

B

7 units

C

11 units

D

1 unit

Text Solution

AI Generated Solution

The correct Answer is:
To find the magnitude of the vector \( \mathbf{a} = 6\hat{i} - 2\hat{j} + 3\hat{k} \), we will follow these steps: ### Step 1: Identify the components of the vector The vector \( \mathbf{a} \) has the following components: - \( a_x = 6 \) (coefficient of \( \hat{i} \)) - \( a_y = -2 \) (coefficient of \( \hat{j} \)) - \( a_z = 3 \) (coefficient of \( \hat{k} \)) ### Step 2: Use the formula for the magnitude of a vector The magnitude of a vector \( \mathbf{a} = a_x \hat{i} + a_y \hat{j} + a_z \hat{k} \) is given by the formula: \[ |\mathbf{a}| = \sqrt{a_x^2 + a_y^2 + a_z^2} \] ### Step 3: Substitute the components into the formula Substituting the values of \( a_x \), \( a_y \), and \( a_z \): \[ |\mathbf{a}| = \sqrt{6^2 + (-2)^2 + 3^2} \] ### Step 4: Calculate the squares of the components Calculating each square: - \( 6^2 = 36 \) - \( (-2)^2 = 4 \) - \( 3^2 = 9 \) ### Step 5: Sum the squares Now, we sum these values: \[ 36 + 4 + 9 = 49 \] ### Step 6: Take the square root Finally, we take the square root of the sum: \[ |\mathbf{a}| = \sqrt{49} = 7 \] ### Conclusion The magnitude of the vector \( \mathbf{a} = 6\hat{i} - 2\hat{j} + 3\hat{k} \) is \( 7 \) units. ### Answer The correct option is (b) 7 units. ---
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Knowledge Check

  • Unit vector along the vector hat(i) + hat(j) + hat(k) is

    A
    `(1)/(3) (hat(i) + hat(k) + hat(k))`
    B
    `(1)/(2) (hat(i) + hat(j) + hat(k))`
    C
    `(1)/(sqrt3) (hat(i) + hat(j) + hat(k))`
    D
    `(1)/(sqrt2) (hat(i) + hat(j) + hat(k))`
  • The vector in the direction of the vector hat(i) - 2 hat(j) + 2hat(k) that has magnitude 9 units is

    A
    `hat(i) - 2 hat(j) + 2 hat(k)`
    B
    `(hat(i) - 2 hat(j) + 2 hat(k))/(3)`
    C
    `3( hat(i)- 2 hat(j) + 2 hat(k))`
    D
    `9 ( hat(i) - 2 hat(j) + 2 hat(k))`
  • Unit vector perpendicular to the vectors hat(i) - hat(j) and hat(i) + hat(j) is

    A
    `hat(k)`
    B
    `- hat(k)`
    C
    `(hat(i) - hat(j))/( sqrt(2))`
    D
    `(hat(i) + hat(j))/( sqrt(2))`
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