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The ratio of milk and water in a mixture...

The ratio of milk and water in a mixture is `5 : 3`. How much fraction of the mixture must be drawn off and substituted by water so that the ratio of milk and water in the mixture becomes `1 : 1`?

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To solve the problem step by step, we will follow the reasoning laid out in the video transcript. ### Step 1: Understand the initial ratio The initial ratio of milk to water in the mixture is given as \(5:3\). This means that for every 8 parts of the mixture, 5 parts are milk and 3 parts are water. ### Step 2: Define the total volume of the mixture Let’s assume the total volume of the mixture is 8 liters. This is a convenient number because it matches the total parts of the ratio (5 + 3 = 8). ### Step 3: Calculate the initial quantities of milk and water From the ratio: - Quantity of milk = \(\frac{5}{8} \times 8 = 5\) liters - Quantity of water = \(\frac{3}{8} \times 8 = 3\) liters ### Step 4: Define the amount of mixture to be drawn off Let \(x\) liters of the mixture be drawn off and replaced with water. ### Step 5: Calculate the quantities of milk and water removed When \(x\) liters of the mixture is drawn off, the quantity of milk and water removed can be calculated as follows: - Milk removed = \(\frac{5}{8}x\) liters - Water removed = \(\frac{3}{8}x\) liters ### Step 6: Calculate the new quantities of milk and water after drawing off After removing \(x\) liters of the mixture and adding \(x\) liters of water, the new quantities will be: - New quantity of milk = \(5 - \frac{5}{8}x\) liters - New quantity of water = \(3 - \frac{3}{8}x + x\) liters - Simplifying this gives: - New quantity of water = \(3 - \frac{3}{8}x + \frac{8}{8}x = 3 + \frac{5}{8}x\) liters ### Step 7: Set up the equation for the new ratio We want the new ratio of milk to water to be \(1:1\). Therefore, we set up the equation: \[ 5 - \frac{5}{8}x = 3 + \frac{5}{8}x \] ### Step 8: Solve the equation To solve for \(x\), we first combine like terms: \[ 5 - 3 = \frac{5}{8}x + \frac{5}{8}x \] \[ 2 = \frac{10}{8}x \] \[ 2 = \frac{5}{4}x \] Multiplying both sides by \(\frac{4}{5}\): \[ x = \frac{8}{5} \text{ liters} \] ### Step 9: Calculate the fraction of the mixture drawn off The fraction of the mixture that was replaced is: \[ \text{Fraction drawn off} = \frac{x}{\text{Total mixture}} = \frac{\frac{8}{5}}{8} = \frac{8}{5} \times \frac{1}{8} = \frac{1}{5} \] ### Final Answer The fraction of the mixture that must be drawn off and substituted by water to achieve a \(1:1\) ratio of milk to water is \(\frac{1}{5}\). ---
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Knowledge Check

  • The ratio of milk and water in a mixture is 3 : 1 . How much fraction of the mixture must be drawn off and substituted by water so that the ratio of milk and water in the mixture becomes 1 : 1 ?

    A
    1/4
    B
    1/3
    C
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    D
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  • The ratio of milk and water in a mixture is 2 : 1 .How much fraction of the mixture must be drawn offand substituted by water so that the ratio of milk and water in the mixture becomes 5 : 3 ?

    A
    1/2
    B
    3/8
    C
    5/12
    D
    5/16
  • A barrel contains a mixture of wine and water in the ratio 3: 1. How much fraction of the mixture must be drawn off and substituted by water so that the ratio of wine and water in the resultant mixture in the barrel becomes 1:1?

    A
    `1/4`
    B
    `1/3`
    C
    `3/4`
    D
    `2/3`
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