Home
Class 12
MATHS
In the following two A.P. 's ow many te...

In the following two A.P. 's ow many terms are identical ?
`2,5,8,11…` to 60 terms and `3,5,7,…..50` terms

Text Solution

AI Generated Solution

The correct Answer is:
To find how many terms are identical in the two given arithmetic progressions (A.P.s), we will follow these steps: ### Step 1: Identify the first A.P. and its properties The first A.P. is given as: \[ 2, 5, 8, 11, \ldots \] - First term \( a_1 = 2 \) - Common difference \( d_1 = 5 - 2 = 3 \) - Number of terms \( n_1 = 60 \) The general term of the first A.P. can be expressed as: \[ a_n = a_1 + (n-1)d_1 = 2 + (n-1) \cdot 3 = 3n - 1 \] ### Step 2: Identify the second A.P. and its properties The second A.P. is given as: \[ 3, 5, 7, \ldots \] - First term \( a_2 = 3 \) - Common difference \( d_2 = 5 - 3 = 2 \) - Number of terms \( n_2 = 50 \) The general term of the second A.P. can be expressed as: \[ b_m = a_2 + (m-1)d_2 = 3 + (m-1) \cdot 2 = 2m + 1 \] ### Step 3: Set the general terms equal to find common terms To find the common terms, we set the general terms equal to each other: \[ 3n - 1 = 2m + 1 \] ### Step 4: Rearranging the equation Rearranging gives: \[ 3n - 2m = 2 \] ### Step 5: Solve for \( n \) in terms of \( m \) From the equation \( 3n - 2m = 2 \), we can express \( n \) in terms of \( m \): \[ 3n = 2m + 2 \] \[ n = \frac{2m + 2}{3} \] ### Step 6: Determine valid values of \( m \) Since \( n \) must be a positive integer and \( n \) can take values from 1 to 60, we need \( 2m + 2 \) to be divisible by 3. Let’s analyze the values of \( m \): - \( m \) can take values from 1 to 50. - For \( n \) to be an integer, \( 2m + 2 \) must be divisible by 3. ### Step 7: Check divisibility condition We can check the values of \( m \): - \( 2m + 2 \equiv 0 \mod 3 \) - This simplifies to \( 2m \equiv 1 \mod 3 \) The solutions for \( m \) modulo 3 are: - \( m \equiv 2 \mod 3 \) (i.e., \( m = 2, 5, 8, \ldots, 50 \)) ### Step 8: Count the valid \( m \) values The sequence \( 2, 5, 8, \ldots, 50 \) is an arithmetic sequence where: - First term \( = 2 \) - Common difference \( = 3 \) To find the number of terms: Let \( k \) be the number of terms: \[ 2 + (k-1) \cdot 3 = 50 \] \[ (k-1) \cdot 3 = 48 \] \[ k-1 = 16 \] \[ k = 17 \] ### Conclusion Thus, the number of identical terms in the two A.P.s is **17**.
Promotional Banner

Topper's Solved these Questions

  • SEQUENCE & SERIES

    RESONANCE|Exercise EXERCISE -1 PART -II RMO|3 Videos
  • SEQUENCE & SERIES

    RESONANCE|Exercise EXERCISE -2 (PART -I PREVIOUS ASKED QUESTION FOR PRE RMO)|18 Videos
  • SEQUENCE & SERIES

    RESONANCE|Exercise SELF PRACTICE PROBLEMS |22 Videos
  • RELATION, FUNCTION & ITF

    RESONANCE|Exercise SSP|55 Videos
  • TEST PAPER

    RESONANCE|Exercise CHEMISTRY|37 Videos

Similar Questions

Explore conceptually related problems

In the following two A.P. 's how many terms are identical 2,5,8,11.... to 60 terms and 3,5,7,.....50 terms

How many terms are identical in the two APs 1,3, 5,... up to 120 terms and 3, 6, 9, .... up to 80 terms ?

How many terms are there in the A.P.3,7,11...407?

Number of identical terms in the sequence 2, 5, 8, 11, ... up to 100 terms and 3, 5, 7, 9, 11, ... Up to 100 terms is

Find the sum of the following A.P.'s : (i) 3,8,13, .... to 20 terms. (ii) 1,4,7,......... to 50 terms. (iii) 8,5,2, .... to 25 terms. (iv) (a+b), (2a+3b), (3b+5b), ........ to n terms.

Find the number of common terms in the following sequences : 3, 7, 11, ... to 100 terms and 2, 5, 8, ... to 100 terms.

For the following A.P.'s , write the first term and common difference : (i) 2, 5, 8, 11, .... (ii) -5, -1, 3, 7, ..... (iii) 0.6, 1.7, 2.8, 3.9, ...... (iv) 5, 2, -1, -4, .....

Find the sum of indicated number of terms of each of the following A.P.'s (i) 5,2,-1,-4,-7,…………., n terms (ii) -1,1/4,3/2,…………..,81 terms (iii) 2,4,6,…………,100 terms (iv) -0.5,-1.0,-1.5,……………, 10 terms ; 50 terms (v) x+y,x-y,x-3y,..................22 terms

For the following A.P.'s write the first term and the common difference: -5,-1,3,7……

RESONANCE-SEQUENCE & SERIES -EXERCISE -1 PART -I RMO
  1. In the following two A.P. 's ow many terms are identical ? 2,5,8,11...

    Text Solution

    |

  2. The vlaue of 9^(1//3)xx9^(1//9)xx9^(1//27)xx………oo is :

    Text Solution

    |

  3. The sum of 10 terms of the series 0.7+ 0.77+ 0.777+………is -

    Text Solution

    |

  4. n^(t h) terms of the series 1+4/5+7/(5^2)+(10)/(5^3)+ ......... will b...

    Text Solution

    |

  5. The sum of infinite terms of the series 5 - 7/3 + (9)/(3 ^(2)) - (11)/...

    Text Solution

    |

  6. The sum of the series 1.2 + 2.3+ 3.4+…….. up to 20 tems is

    Text Solution

    |

  7. sum (r = 2) ^(oo) (1)/(r ^(2) - 1) is equal to :

    Text Solution

    |

  8. If (1 ^(2) - t (1)) + (2 ^(2) - t (2)) + ......+ ( n ^(2) - t (n)) =(...

    Text Solution

    |

  9. If x gt 0, then the expression (x ^(100))/( 1 + x + x ^(2) +x ^(3) + ....

    Text Solution

    |

  10. Given the sequence a, ab, aab, aabb, aaabb,aaabbb,…. Upto 2004 terms, ...

    Text Solution

    |

  11. A sequence a (0) , a(1), a (2), a(3)………..a (n) …. is defined such that...

    Text Solution

    |

  12. The first two terms of a sequence are 0 and 1, The n ^(th) terms T (n)...

    Text Solution

    |

  13. Consider the following sequence :a (1) = a (2) =1, a (i) = 1 + minimum...

    Text Solution

    |

  14. The sum of (1)/( 2sqrt1+1 sqrt2 ) + (1)/( 3 sqrt2 + 2 sqrt3 ) + (1)/(...

    Text Solution

    |

  15. If f (x) + f (1 - x) is equal to 10 for all real numbers x then f ((1)...

    Text Solution

    |

  16. Consider the sequence 4,4,8,0,2,2,4,6,0,….. where the nth term is the ...

    Text Solution

    |

  17. For some natureal number 'n', the sum of the fist 'n' natural numbers ...

    Text Solution

    |

  18. An arithmetical progression has positive terms. The ratio of the diffe...

    Text Solution

    |

  19. The 12 numbers, a (1), a (2)………, a (12) are in arithmetical progressio...

    Text Solution

    |

  20. Each term of a sequence is the sum of its preceding two terms from the...

    Text Solution

    |