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In the following two A.P. 's ow many te...

In the following two A.P. 's ow many terms are identical ?
`2,5,8,11…` to 60 terms and `3,5,7,…..50` terms

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To find how many terms are identical in the two given arithmetic progressions (A.P.s), we will follow these steps: ### Step 1: Identify the first A.P. and its properties The first A.P. is given as: \[ 2, 5, 8, 11, \ldots \] - First term \( a_1 = 2 \) - Common difference \( d_1 = 5 - 2 = 3 \) - Number of terms \( n_1 = 60 \) The general term of the first A.P. can be expressed as: \[ a_n = a_1 + (n-1)d_1 = 2 + (n-1) \cdot 3 = 3n - 1 \] ### Step 2: Identify the second A.P. and its properties The second A.P. is given as: \[ 3, 5, 7, \ldots \] - First term \( a_2 = 3 \) - Common difference \( d_2 = 5 - 3 = 2 \) - Number of terms \( n_2 = 50 \) The general term of the second A.P. can be expressed as: \[ b_m = a_2 + (m-1)d_2 = 3 + (m-1) \cdot 2 = 2m + 1 \] ### Step 3: Set the general terms equal to find common terms To find the common terms, we set the general terms equal to each other: \[ 3n - 1 = 2m + 1 \] ### Step 4: Rearranging the equation Rearranging gives: \[ 3n - 2m = 2 \] ### Step 5: Solve for \( n \) in terms of \( m \) From the equation \( 3n - 2m = 2 \), we can express \( n \) in terms of \( m \): \[ 3n = 2m + 2 \] \[ n = \frac{2m + 2}{3} \] ### Step 6: Determine valid values of \( m \) Since \( n \) must be a positive integer and \( n \) can take values from 1 to 60, we need \( 2m + 2 \) to be divisible by 3. Let’s analyze the values of \( m \): - \( m \) can take values from 1 to 50. - For \( n \) to be an integer, \( 2m + 2 \) must be divisible by 3. ### Step 7: Check divisibility condition We can check the values of \( m \): - \( 2m + 2 \equiv 0 \mod 3 \) - This simplifies to \( 2m \equiv 1 \mod 3 \) The solutions for \( m \) modulo 3 are: - \( m \equiv 2 \mod 3 \) (i.e., \( m = 2, 5, 8, \ldots, 50 \)) ### Step 8: Count the valid \( m \) values The sequence \( 2, 5, 8, \ldots, 50 \) is an arithmetic sequence where: - First term \( = 2 \) - Common difference \( = 3 \) To find the number of terms: Let \( k \) be the number of terms: \[ 2 + (k-1) \cdot 3 = 50 \] \[ (k-1) \cdot 3 = 48 \] \[ k-1 = 16 \] \[ k = 17 \] ### Conclusion Thus, the number of identical terms in the two A.P.s is **17**.
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In the following two A.P. 's how many terms are identical 2,5,8,11.... to 60 terms and 3,5,7,.....50 terms

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Knowledge Check

  • How many terms are identical in the two APs 1,3, 5,... up to 120 terms and 3, 6, 9, .... up to 80 terms ?

    A
    A)38
    B
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    30
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    40
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    50
    D
    60
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    A
    33
    B
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    C
    50
    D
    147
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