In changing the state of a gas adiabatically from an equilibrium state A to another equilibrium state B, an amount of work equal to 22.3 J is done on the system. If the gas is taken from state A to B, via a process in which the net heat absorbed by the system is 9.35 cal, how much is the net work done by the system in the latter case ?

Explanation

To solve the problem step by step, we will use the principles of thermodynamics, particularly the first law of thermodynamics, which states that the change in internal energy (ΔU) of a system is equal to the heat added to the system (Q) minus the work done by the system (W).

### Step 1: Understand the adiabatic process
In the adiabatic process from state A to state B, the work done on the system is given as 22.3 J. Since it is an adiabatic process, there is no heat exchange (Q = 0). Therefore, the change in internal energy (ΔU) can be expressed as:
\[ \Delta U = -W = -(-22.3 \, \text{J}) = 22.3 \, \text{J} \]

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