Home
Class 11
PHYSICS
What is the efficiency of a carnot engin...

What is the efficiency of a carnot engine working between ice point and steam point ?

Text Solution

AI Generated Solution

To find the efficiency of a Carnot engine working between the ice point and steam point, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Temperatures**: - The ice point corresponds to a temperature of 0°C, which is equivalent to 273 Kelvin (K). - The steam point corresponds to a temperature of 100°C, which is equivalent to 373 Kelvin (K). ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • INTERNAL ENERGY

    ICSE|Exercise SELECTED PROBLEMS (FROM WORK DONE AND INDICATOR DIAGRAM )|13 Videos
  • GRAVITATION

    ICSE|Exercise FROM THE HUBBLE TELESCOP|2 Videos
  • MOTION IN FLUIDS

    ICSE|Exercise SELECTED PROBLEMS (FROM POISEUILLE.S FORMULA) |19 Videos

Similar Questions

Explore conceptually related problems

The efficiency of a Carnot engine working between 800 K and 500 K is -

The efficiency of carnot engine depends on

Knowledge Check

  • Efficiency of carnot engine working between ice point and steam point is

    A
    0.249
    B
    0.257
    C
    0.268
    D
    0.288
  • The efficiencty of a carnot engine working between 127^(@) C and 77^(@) C is

    A
    0.105
    B
    0.125
    C
    0.268
    D
    0.135
  • Similar Questions

    Explore conceptually related problems

    Calculate the efficiency of a carnot engine working between the two temperatures: 30^(@)Cand 100^(@)C

    The efficiency of an ideal heat engine working between the freezing point and boiling point of water, is

    Efficiency of a Carnot heat engine may be given as

    The efficiency of a heat engine is defined as the ratio of the mechanical work done by the engine in one cycle to the heat absorbed from the high temperature source . eta = (W)/(Q_(1)) = (Q_(1) - Q_(2))/(Q_(1)) Cornot devised an ideal engine which is based on a reversible cycle of four operations in succession: isothermal expansion , adiabatic expansion. isothermal compression and adiabatic compression. For carnot cycle (Q_(1))/(T_(1)) = (Q_(2))/(T_(2)) . Thus eta = (Q_(1) - Q_(2))/(Q_(1)) = (T_(1) - T_(2))/(T_(1)) According to carnot theorem "No irreversible engine can have efficiency greater than carnot reversible engine working between same hot and cold reservoirs". Efficiency of a carnot's cycle change from (1)/(6) to (1)/(3) when source temperature is raised by 100K . The temperature of the sink is-

    What should be the condition for the efficiency of a carnot engine to be equal to 1 ?

    If the efficiency of a carnot engine is eta ,then the coefficient of performance of a heat pump working between the same temperatures will be