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How many mL of 1.M sulphuric acid is req...

How many mL of 1.M sulphuric acid is required t neutralise 10 mL of 1 M sodium hydroxide solution ?

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AI Generated Solution

To determine how many mL of 1 M sulfuric acid (H₂SO₄) is required to neutralize 10 mL of 1 M sodium hydroxide (NaOH) solution, we can follow these steps: ### Step 1: Write the balanced chemical equation The balanced chemical equation for the neutralization reaction between sulfuric acid and sodium hydroxide is: \[ \text{H}_2\text{SO}_4 + 2 \text{NaOH} \rightarrow \text{Na}_2\text{SO}_4 + 2 \text{H}_2\text{O} \] This equation shows that one mole of sulfuric acid reacts with two moles of sodium hydroxide. ...
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12 mL of 0.2 N sulphuric acid is neutralised with 15 mL of sodium hydroxide solution on titration. Calculate the normality of sodium hydroxide solution.

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Knowledge Check

  • Which one of the following solutions of sulphuric acid will exactly neutralise 25 ml of 0.2 M sodium hydroxide solution ?

    A
    12.5ml of 0.1M solution
    B
    25ml of 0.1 M solution
    C
    25ml of 0.2 M solution
    D
    50 ml of 0.2 M solution
  • If 100mL of 1N sulphuric acid were mixed with 100mL of 1N sodium hydroxide, the solution will be

    A
    Acidic
    B
    Basic
    C
    Neutral
    D
    Slightly acidic
  • The ammonia evolved from the treatment of 0.30 g of an organic compound for the estimation of nitrogen was passed in 100 mL of 0.1 M sulphuric acid. The excess of acid required 20 mL of 0.5 M sodium hydroxide solution for complete neutralization. The organic compound is :

    A
    acetamide
    B
    benzamide
    C
    urea
    D
    thiourea
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