The net optical rotation of a racemic mixture is zero due to external compensation. True/False

Explanation

To determine whether the statement "The net optical rotation of a racemic mixture is zero due to external compensation" is true or false, we can analyze the concepts involved step by step.

### Step 1: Understand Racemic Mixtures
A racemic mixture consists of equal amounts of two enantiomers, which are molecules that are mirror images of each other. For example, if we have enantiomer A and enantiomer B, a racemic mixture would contain 50% A and 50% B.

**Hint:** Remember that enantiomers are chiral molecules that rotate plane-polarized light in opposite directions.

### Step 2: Optical Rotation of Enantiomers
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