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The specific conductance of a 0.01 M sol...

The specific conductance of a 0.01 M solution of acetic acid at 298K is `1.65xx10^(-4)ohm^(-1)cm^(-1)`. The molar conductance at infinite dilution fo `H^(+)` ion and `CH_(3)COO^(-)` ion are 349.1 `ohm^(-1)cm^(2)mol^(-1)` and `40.9ohm^(-1)cm^(2)mol^(-1)` respectively.
Calculate :
Molar conductance of the solution.

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To calculate the molar conductance of the 0.01 M solution of acetic acid, we can use the formula: \[ \Lambda_m = \frac{\kappa \times 1000}{C} \] where: - \(\Lambda_m\) is the molar conductance, ...
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The specific conductance of a 0.01 M solution of acetic acid at 298K is 1.65xx10^(-4)ohm^(-1)cm^(-1) . The molar conductance at infinite dilution fo H^(+) ion and CH_(3)COO^(-) ion are 349.1 ohm^(-1)cm^(2)mol^(-1) and 40.9ohm^(-1)cm^(2)mol^(-1) respectively. Calculate : Dissociation constant for acetic acid.

The specific conductance of a 0.01 M solution of acetic acid at 298 K is 1.65 xx 10^(-4) "ohm"^(-1)cm^(-1) . The molar conductance at infinite dilution for H^(+) ion and CH_(3)COO^(-) ion are 349.1 "ohm"^(-1) cm^(2 )"mol"^(-1) and 40.9 "ohm"^(-1) cm^(2) "mol"^(-1) respectively. Calculate : (i) Molar conductance of solution (ii) Degree of dissociation of acetic acid (iii) Dissociation constant for acetic acid.

Knowledge Check

  • Specific conductance of 0.1 M NaCl solution is 1.01xx10^(-2) ohm^(-1) cm^(-1) . Its molar conductance in ohm^(-1) cm^(2) mol^(-1) is

    A
    `1.01xx10^2`
    B
    `1.01xx10^3`
    C
    `1.01xx10^4`
    D
    `1.01`

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    The specific conductance of a 0.01 M solution of acetic acid at 298K is 1.65xx10^(-4)ohm^(-1)cm^(-1) . The molar conductance at infinite dilution fo H^(+) ion and CH_(3)COO^(-) ion are 349.1 ohm^(-1)cm^(2)mol^(-1) and 40.9ohm^(-1)cm^(2)mol^(-1) respectively. Calculate : Degree of dissociation of CH_(3)COOH .

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