Home
Class 12
CHEMISTRY
An organic compound A has the molecular ...

An organic compound A has the molecular formula of `C_7H_6O`. When A is treated with NaOH followed by acid hydrolysis, it gives two products, B and C. When B is oxidised, it gives A. When A and C are each treated separately with `PCl_5`, they give two different organic products D and E.
Identify A to E.

Text Solution

Verified by Experts

(A) = `C_(6)H_(5)CHO`
(B) = `C_(6)H_(5)CH_(2)OH`
(C ) = `C_(6)H_(5)COOH`
(D) = `C_(6)H_(5)CHCl_(2)`
(E) = `C_(6)H_(5)COCl`
Promotional Banner

Topper's Solved these Questions

  • SAMPLE PAPER 2016

    ICSE|Exercise PART-II SECTION-C QUESTION 9. |7 Videos

  • SAMPLE PAPER 2015

    ICSE|Exercise PART-II SECTION-C QUESTION 10. |7 Videos

  • SAMPLE PAPER 4 (CHEMISTRY)

    ICSE|Exercise QUESTIONS|70 Videos

Similar Questions

Explore conceptually related problems

An organic compound A has the molecular formula of C_7H_6O . When A is treated with NaOH followed by acid hydrolysis, it gives two products, B and C. When B is oxidised, it gives A. When A and C are each treated separately with PCl_5 , they give two different organic products D and E. Give the chemical reaction when A is treated with NaOH and name the reaction.

When is treated with C_2H_5Mg Br , followed by hydrolysis, the product is :

When ethane nitrile is treated with C_2H_5 MgBr , followed by hydrolysis, the product is :

1-Ethyl-2-methyl oxirane when treated with C_2 H_5 MgBr , followed by hydrolysis gives :

An organic compound with molecular formula C_6 H_(12) upon ozonolysis gives only acetone as the product. The compound is :

Compound 'A' reacts with PCl_(5) to given 'B' which on treatment with KCN followed by hydrolysis give propanoic acid as the product. What is 'A'?

Name the two organic compounds which have the same molecular formula C_(2)H_(6)O . Will they react with PCl_(5) ? If they react, what are the products formed ?

(i) An organic compound A with molecular formula C_(7)H_(8) on oxidation by chromyl chloride in the presence of C Cl_(4) gives a compound B which gives positive Tollen's test. The compound B on treatment with NaOH followed by acid hydrolysis gives two product C and D. C on oxidation gives B which on further oxidation gives D. the compound D on distillation with sodalime gives a hydrocarbon E. Below 60^(@)C , concentrated nitric acid reacts with E in the presence of concentrated sulphuric acid forming a compound F. identify the compounds A,B,C,D,E and F. (ii) Give chemical test to distinguish : Formaldehyde and acetaldehyde.

Compound 'A' of molecular formula C_(4)H_(10)O on treatment with Lucas reagent at room temperature gives compound 'B'. When compound 'B' is heated with alcoholic KOH, it gives isobutene. Compound 'A' and 'B' are respectively :

An organic compound [A] with molecular formula C_(4)H_(8)O when reduced with NaBH_(4) gives compound [B] which reacts with HBr to form compound [C] (optically active) Identify A,B , C and wirte the two enantimoers of compound [C].