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Statement 1 : In DeltaABC, vec(AB) + vec...

Statement 1 : In `DeltaABC`, `vec(AB) + vec(BC) + vec(CA) = 0`
Statement 2 : If `vec(OA) = veca, vec(OB) = vecb`, then `vec(AB) = veca + vecb`

A

Both Statement I and Statement II are correct and statement II is the correct explanation of statement I

B

Both statement I and statement II are correct but statement II is not the correct explanation of statement I

C

Statement I is correct but statement II is incorrect

D

Statement II is correct but statement I is incorrect

Text Solution

Verified by Experts

The correct Answer is:
C
In `DeltaABC,AB+BC=AC=-CA`
or `AB+BC+CA=0`
OA+AB=OB is the triangle law of addition.
Hence, statement 1 is true and statement 2 is false.
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Knowledge Check

  • If OACB is a parallelogrma with vec( OC) = vec(a) and vec( AB) = vec(b) then vec(OA) is equal to

    A
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    B
    `vec( a) - vec( b)`
    C
    `(1)/(2) vec( a) - vec( b)`
    D
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