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The function f(x)=e^x+x , being differen...

The function `f(x)=e^x+x ,` being differentiable and one-to-one, has a differentiable inverse `f^(-1)(x)dot` The value of `d/(dx)(f^(-1))` at the point `f(log2)` is `1/(1n2)` (b) `1/3` (c) `1/4` (d) none of these

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The correct Answer is:
`(1)/(3)`
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