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The slope of the tangent to the curve (y...

The slope of the tangent to the curve `(y-x^5)^2=x(1+x^2)^2` at the point `(1,3)` is.

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Knowledge Check

  • The slope of the tangent to the curve y=x^(3) -x +1 at the point whose x-coordinate is 2 is

    A
    `-11`
    B
    `(1)/(11)`
    C
    11
    D
    `3x^(2)-1`

  • The slope of the normal to the curve x^(2) + 3y + y^(2) = 5 at the point (1,1) is

    A
    `-(2)/(3)`
    B
    `(5)/(2)`
    C
    `(2)/(5)`
    D
    `-(5)/(2)`

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    Find the equation of the tangent to the curve y=-5x^2+6x+7 at the point (1//2,\ 35//4) .

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