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If barx=18,bary=100, sigma(x)=14,sigma(y...

If `barx=18,bary=100, sigma_(x)=14,sigma_(y)=20` and correlation `r_(xy)=0.8`, find the regression equation of y on x.

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To find the regression equation of \( y \) on \( x \), we will follow these steps: ### Step 1: Write down the regression equation formula The regression equation of \( y \) on \( x \) can be expressed as: \[ y - \bar{y} = b_{yx}(x - \bar{x}) \] where \( b_{yx} \) is the regression coefficient of \( y \) on \( x \), \( \bar{y} \) is the mean of \( y \), and \( \bar{x} \) is the mean of \( x \). ### Step 2: Calculate the regression coefficient \( b_{yx} \) The regression coefficient \( b_{yx} \) can be calculated using the formula: \[ b_{yx} = r_{xy} \cdot \frac{\sigma_y}{\sigma_x} \] where: - \( r_{xy} \) is the correlation coefficient, - \( \sigma_y \) is the standard deviation of \( y \), - \( \sigma_x \) is the standard deviation of \( x \). Given: - \( r_{xy} = 0.8 \) - \( \sigma_y = 20 \) - \( \sigma_x = 14 \) Substituting the values: \[ b_{yx} = 0.8 \cdot \frac{20}{14} \] Calculating this gives: \[ b_{yx} = 0.8 \cdot 1.42857 \approx 1.143 \] ### Step 3: Substitute the values into the regression equation Now we substitute \( b_{yx} \), \( \bar{y} \), and \( \bar{x} \) into the regression equation: - \( \bar{y} = 100 \) - \( \bar{x} = 18 \) The equation becomes: \[ y - 100 = 1.143(x - 18) \] ### Step 4: Simplify the equation Expanding the right side: \[ y - 100 = 1.143x - 1.143 \cdot 18 \] Calculating \( 1.143 \cdot 18 \): \[ 1.143 \cdot 18 \approx 20.574 \] Thus, we have: \[ y - 100 = 1.143x - 20.574 \] Adding 100 to both sides: \[ y = 1.143x + 100 - 20.574 \] Calculating \( 100 - 20.574 \): \[ y = 1.143x + 79.426 \] ### Final Answer The regression equation of \( y \) on \( x \) is: \[ y = 1.143x + 79.426 \]
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Knowledge Check

  • If sigma_(x) = 3, sigma_(y) = 4 , and b_(xy) = (1)/(3) , then the value of r is

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    `(9)/(4)`
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    ` sqrt(10)`
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    ` 10 `
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