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Sum of all the odd divisors of 720 is...

Sum of all the odd divisors of 720 is

A

76

B

78

C

80

D

84

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • 2^m3^n5^p is a divisor of 2^10 cdot 3^8 cdot 5^7 if m, n and p are all whole number such that 0 le m le 10, 0 le n le 8 and 0 le p le 7 . also, (2^0 + 2^1 +.........+2^10)(3^0 + 3^1 +.......+3^8)(5^0+5^1+....+5^7) = sum of all the divisors of 2^10 cdot 3^8 cdot 5^7 The sum of odd divisors (ne 1) of 10800 is

    A
    1239
    B
    1240
    C
    1238
    D
    2479

  • 2^m3^n5^p is a divisor of 2^10 cdot 3^8 cdot 5^7 if m, n and p are all whole number such that 0 le m le 10, 0 le n le 8 and 0 le p le 7 . also, (2^0 + 2^1 +.........+2^10)(3^0 + 3^1 +.......+3^8)(5^0+5^1+....+5^7) = sum of all the divisors of 2^10 cdot 3^8 cdot 5^7 The number of proper divisors of 16200 is

    A
    60
    B
    24
    C
    58
    D
    22

  • The number of even divisors of 10800 is

    A
    12
    B
    24
    C
    36
    D
    48

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