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Let Z1 and Z2 are two non-zero complex n...

Let `Z_1` and `Z_2` are two non-zero complex number such that `|Z_1+Z_2|=|Z_1|=|Z_2|`, then `Z_1/Z_2` may be :

A

`1 + omega`

B

`1+ omega^2`

C

`omega`

D

`omega^2`

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze the conditions given for the complex numbers \( Z_1 \) and \( Z_2 \). We know that: 1. \( |Z_1 + Z_2| = |Z_1| \) 2. \( |Z_1 + Z_2| = |Z_2| \) From these conditions, we can derive the possible values for \( \frac{Z_1}{Z_2} \). ### Step-by-Step Solution: **Step 1: Understanding the Conditions** Given \( |Z_1 + Z_2| = |Z_1| = |Z_2| \), we can denote \( |Z_1| = |Z_2| = r \) for some positive real number \( r \). **Hint:** Recognize that the magnitudes of \( Z_1 \) and \( Z_2 \) are equal. --- **Step 2: Using the Triangle Inequality** From the triangle inequality, we know that: \[ |Z_1 + Z_2| \leq |Z_1| + |Z_2| = r + r = 2r \] However, since \( |Z_1 + Z_2| = r \), we have: \[ r \leq 2r \] This is always true, but we also know from the equality condition of the triangle inequality that \( Z_1 \) and \( Z_2 \) must be in the same direction in the complex plane. **Hint:** Consider the implications of the triangle equality. --- **Step 3: Expressing \( Z_1 \) and \( Z_2 \)** Let’s express \( Z_1 \) and \( Z_2 \) in terms of a common angle. We can set: \[ Z_1 = r e^{i\theta}, \quad Z_2 = r e^{i\phi} \] Since \( |Z_1| = |Z_2| = r \). **Hint:** Use polar form to express complex numbers. --- **Step 4: Analyzing the Condition \( |Z_1 + Z_2| = r \)** Now we have: \[ |Z_1 + Z_2| = |r e^{i\theta} + r e^{i\phi}| = r |e^{i\theta} + e^{i\phi}| \] Setting this equal to \( r \): \[ |e^{i\theta} + e^{i\phi}| = 1 \] This implies that \( e^{i\theta} + e^{i\phi} \) must lie on the unit circle. **Hint:** Consider the geometric interpretation of complex numbers on the unit circle. --- **Step 5: Finding the Ratio \( \frac{Z_1}{Z_2} \)** Now, we can find the ratio: \[ \frac{Z_1}{Z_2} = \frac{r e^{i\theta}}{r e^{i\phi}} = e^{i(\theta - \phi)} \] Since \( |e^{i\theta} + e^{i\phi}| = 1 \), we can conclude that \( \theta - \phi \) can take specific values that correspond to the angles of the cube roots of unity. **Hint:** Think about the angles that satisfy the conditions derived. --- **Step 6: Possible Values of \( \frac{Z_1}{Z_2} \)** The possible values of \( \frac{Z_1}{Z_2} \) can be determined by the cube roots of unity: 1. \( \omega = e^{2\pi i / 3} \) 2. \( \omega^2 = e^{-2\pi i / 3} \) Thus, \( \frac{Z_1}{Z_2} \) can be either \( \omega \) or \( \omega^2 \). **Hint:** Recall the properties of cube roots of unity. --- ### Final Answer: The values that \( \frac{Z_1}{Z_2} \) may take are \( \omega \) and \( \omega^2 \), which correspond to option 3 and option 4.
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