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Let y=f(x) be a real valued function sat...

Let y=f(x) be a real valued function satisfying `xdy/dx = x^2 + y-2`, f(1)=1 then f(3) equal

A

8

B

7

C

5

D

2

Text Solution

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The correct Answer is:
To solve the differential equation given by \( x \frac{dy}{dx} = x^2 + y - 2 \) with the initial condition \( f(1) = 1 \), we will follow these steps: ### Step 1: Rewrite the Differential Equation We start with the equation: \[ x \frac{dy}{dx} = x^2 + y - 2 \] We can rearrange it to isolate \( \frac{dy}{dx} \): \[ \frac{dy}{dx} = \frac{x^2 + y - 2}{x} \] This simplifies to: \[ \frac{dy}{dx} = x + \frac{y}{x} - \frac{2}{x} \] ### Step 2: Identify the Form of the Equation The equation can be rewritten as: \[ \frac{dy}{dx} - \frac{y}{x} = x - \frac{2}{x} \] This is a linear first-order differential equation of the form: \[ \frac{dy}{dx} + P(x)y = Q(x) \] where \( P(x) = -\frac{1}{x} \) and \( Q(x) = x - \frac{2}{x} \). ### Step 3: Find the Integrating Factor The integrating factor \( \mu(x) \) is given by: \[ \mu(x) = e^{\int P(x) \, dx} = e^{\int -\frac{1}{x} \, dx} = e^{-\ln|x|} = \frac{1}{x} \] ### Step 4: Multiply the Equation by the Integrating Factor Multiplying the entire differential equation by the integrating factor \( \frac{1}{x} \): \[ \frac{1}{x} \frac{dy}{dx} - \frac{y}{x^2} = 1 - \frac{2}{x^2} \] ### Step 5: Rewrite the Left Side The left side can be expressed as: \[ \frac{d}{dx} \left( \frac{y}{x} \right) = 1 - \frac{2}{x^2} \] ### Step 6: Integrate Both Sides Integrating both sides gives: \[ \frac{y}{x} = \int \left( 1 - \frac{2}{x^2} \right) dx \] Calculating the integral: \[ \int \left( 1 - \frac{2}{x^2} \right) dx = x + \frac{2}{x} + C \] Thus, we have: \[ \frac{y}{x} = x + \frac{2}{x} + C \] ### Step 7: Solve for \( y \) Multiplying through by \( x \): \[ y = x^2 + 2 + Cx \] ### Step 8: Apply the Initial Condition Given \( f(1) = 1 \): \[ 1 = 1^2 + 2 + C(1) \] This simplifies to: \[ 1 = 1 + 2 + C \implies C = -2 \] ### Step 9: Substitute \( C \) Back into the Equation Substituting \( C \) back: \[ y = x^2 + 2 - 2x \] Thus, we have: \[ f(x) = x^2 - 2x + 2 \] ### Step 10: Find \( f(3) \) Now we calculate \( f(3) \): \[ f(3) = 3^2 - 2(3) + 2 = 9 - 6 + 2 = 5 \] ### Final Answer Thus, the value of \( f(3) \) is: \[ \boxed{5} \]
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