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Let log(3)N=alpha(1)+beta(1) log(5)N=...

Let `log_(3)N=alpha_(1)+beta_(1)`
`log_(5)N=alpha_(2)+beta_(2)`
`log_(7)N=alpha_(3)+beta_(3)`
where `alpha_(1), alpha_(2) and alpha_(3)` are integers and `beta_(1), beta_(2), beta_(3) in [0,1)`.
Q. Difference of largest and smallest values of N if `alpha_(1)=5, alpha_(2)=3 and alpha_(3)=2`.

A

46

B

45

C

44

D

47

Text Solution

Verified by Experts

The correct Answer is:
C
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