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p(y)-orbital can not form pi -bond by la...

`p_(y)`-orbital can not form `pi` -bond by lateral overlap with :

A

`d_(xz)`- orbital

B

`d_(x^(2)-y^(2))`-orbitals

C

`d_(xy)`-orbital

D

`p_(z)` -orbital

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding which orbital cannot form a pi bond by lateral overlap with the \( p_y \) orbital, we will analyze each option step by step. ### Step-by-Step Solution: 1. **Understanding Pi Bonds**: - A pi bond is formed by the lateral (sideways) overlap of orbitals. This is crucial for determining which orbitals can interact with the \( p_y \) orbital. 2. **Analyzing Option A: \( d_{xz} + p_y \)**: - The \( d_{xz} \) orbital lies in the x-z plane, while the \( p_y \) orbital is oriented along the y-axis. - Since the \( p_y \) orbital is perpendicular to the x-z plane, when they approach each other, they overlap at a node (where the probability of finding an electron is zero). - This results in zero overlap, meaning no pi bond can be formed. - **Conclusion**: \( p_y \) cannot form a pi bond with \( d_{xz} \). 3. **Analyzing Option B: \( d_{x^2 - y^2} + p_y \)**: - The \( d_{x^2 - y^2} \) orbital is oriented along the x and y axes. - When \( p_y \) (along the y-axis) approaches \( d_{x^2 - y^2} \), they can only overlap head-on, leading to the formation of a sigma bond rather than a pi bond. - **Conclusion**: \( p_y \) cannot form a pi bond with \( d_{x^2 - y^2} \). 4. **Analyzing Option C: \( d_{xy} + p_y \)**: - The \( d_{xy} \) orbital lies in the x-y plane, which is the same plane as the \( p_y \) orbital. - When these orbitals approach each other, they can overlap laterally, allowing for the formation of a pi bond. - **Conclusion**: \( p_y \) can form a pi bond with \( d_{xy} \). 5. **Analyzing Option D: \( p_z + p_y \)**: - The \( p_z \) orbital is oriented along the z-axis, while \( p_y \) is along the y-axis. - When these orbitals approach each other, they also have a node where they do not overlap, resulting in zero overlap. - **Conclusion**: \( p_y \) cannot form a pi bond with \( p_z \). ### Final Answer: The \( p_y \) orbital cannot form a pi bond by lateral overlap with: - **Option A**: \( d_{xz} \) - **Option B**: \( d_{x^2 - y^2} \) - **Option D**: \( p_z \)
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Knowledge Check

  • Which of the following orbitals will not form sigma bond after overlapping ?

    A
    s - orbital and s- orbital
    B
    s- orbital and `p_(z) -` orbital
    C
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    D
    `p_(x)`-orbital and `p_(x)`- orbital
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