The bond length of the S-O bond is maximum in which of the following compounds?

Options

A. `SOCl_(2)`
B. `SOBr_(2)`
C. `SOF_(2)`
D. All have same length

Explanation

To determine the compound with the maximum S-O bond length among the given options (SOCl2, SOBr2, SOF2), we can follow these steps:

### Step 1: Understand the Relationship Between Electronegativity and Bond Length
The bond length is influenced by the electronegativity of the atoms involved in the bond. Higher electronegativity leads to greater s-character in the bond, which in turn results in a shorter bond length. Conversely, lower electronegativity results in a longer bond length.

### Step 2: Identify the Electronegativity of the Atoms
The electronegativity values for the halogens are as follows:
- Fluorine (F) - highest electronegativity
- Chlorine (Cl) - medium electronegativity
- Bromine (Br) - lower electronegativity

### Step 3: Analyze Each Compound
1. **SOF2**: Contains fluorine, which has the highest electronegativity. Therefore, the S-O bond will be the shortest due to high s-character.
2. **SOCl2**: Contains chlorine, which has a lower electronegativity than fluorine but higher than bromine. The S-O bond length will be longer than in SOF2 but shorter than in SOBr2.
3. **SOBr2**: Contains bromine, which has the lowest electronegativity among the three halogens. This results in the longest S-O bond length.

### Step 4: Conclusion
Based on the analysis of electronegativity and its effect on bond length, we can conclude that the S-O bond length is maximum in **SOBr2**.

### Final Answer
The bond length of the S-O bond is maximum in **SOBr2**.

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