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A particle moves in the the x-y plane ac...

A particle moves in the the `x-y` plane according to the scheme `x= 8 sin pit` and y=-2 cos(^2)pit` pit`, where t is time. Find equation of the path of the particle. Show the path on a graph.

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To find the equation of the path of the particle moving in the x-y plane according to the equations \( x = 8 \sin(\pi t) \) and \( y = -2 \cos^2(\pi t) \), we need to eliminate the parameter \( t \) from these equations. ### Step 1: Express \( \sin(\pi t) \) in terms of \( x \) From the equation \( x = 8 \sin(\pi t) \), we can express \( \sin(\pi t) \) as follows: \[ \sin(\pi t) = \frac{x}{8} ...
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Knowledge Check

  • A particle moves in x-y plane according to the equations x= 4t^2+ 5t+ 16 and y=5t where x, y are in metre and t is in second. The acceleration of the particle is

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    B
    `12 m s^(-2)`
    C
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    D
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    A
    1. `x=y^3-y^2+2`
    B
    2. `x=y^2 - y+2`
    C
    3. `x=y^2 - 3y+2`
    D
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