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A solid sphere of uniform density and ra...

A solid sphere of uniform density and radius 4 units is located with its centre at the origin O of coordinates. Two sphere of equal radii 1 unit, with their centres at A(-2,0 ,0) and B(2,0,0) respectively, are taken out of the solid leaving behind spherical cavities as shown if fig Then:

A

the gravitational force due to this object at the origin is zero

B

the gravitational force at point `B (2, 0, 0)` is zero

C

the gravitational potential is the same at all points of circle `y^(2)+z^(2)q=36`

D

Both (a) and (c)

Text Solution

Verified by Experts

The correct Answer is:
A, C, D

The gravitational field intensity at point `O` is zero (as the cavities are symmetrical with respect to `O`).
Now the force acting on a test mass `m_(0)` placed at `O` is given by
`F=m_(0)E=m_(0)xx0=0`
Now `y^(2)+z^(2)=36` represents the equation of a circle with centre `(0,0,0)` and radius `6` units. The plane of the circle is perpendicular to the axis. Since the spherical mass distribution behaves as if the whole mass is at its centre (for a point outside the sphere) and since all the points on the circle are equidistant from the centre of the sphere, the circle is a gravitational equipotential.
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Knowledge Check

  • A solid sphere of uniform density and radius R applies a gravitational force of attraction equal to F_(1) on a particle placed at P , distance 2R from the centre O of the sphere. A spherical cavity of radius R//2 is now made in the sphere as shown in figure. The particle with cavity now applies a gravitational force F_(2) on same particle placed at P . The radio F_(2)//F_(1) will be

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    C
    `3`
    D
    `7`
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