Home
Class 11
PHYSICS
If the radius of the earth were to shrin...

If the radius of the earth were to shrink by 1%, its mass remaining the same, the acceleration due to gravity on the earth's surface would

A

decrease

B

remain unchnaged

C

increase

D

be zero

Text Solution

Verified by Experts

The correct Answer is:
C
`g=(GM)/(R^(2)) g'=(GM)((0.9R)^(2))`
`:.g'/g=((R^(2))/(0.99R))^(2)impliesg'gtR`
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    CENGAGE PHYSICS ENGLISH|Exercise MCQ_TYPE|4 Videos

  • GRAVITATION

    CENGAGE PHYSICS ENGLISH|Exercise AR_TYPE|1 Videos

  • GRAVITATION

    CENGAGE PHYSICS ENGLISH|Exercise True/False|1 Videos

  • FLUID MECHANICS

    CENGAGE PHYSICS ENGLISH|Exercise INTEGER_TYPE|1 Videos

  • KINEMATICS-1

    CENGAGE PHYSICS ENGLISH|Exercise Integer|9 Videos

Similar Questions

Explore conceptually related problems

If the radius of the earth were to shrink by one percent its mass remaining the same, the acceleration due to greavity on the earth's surface would

If the radius of earth were to decrease by 1%, its mass remaining the same, the acceleration due to gravity on the surface of the earth will

If the radius of the earth shrinks by 1.5% (mass remaining same), then the value of acceleration due to gravity changes by

If the radius of the earth shrinks by 1.5% ( mass remaining same) , then the value of acceleration due to gravity changes by

The value of acceleration due to gravity at the surface of earth

If the radius of the earth decreases by 10% , the mass remaining unchanged, what will happen to the acceleration due to gravity?

If the radius of the earth decreases by 1% without changing its mass, will the acceleration dure to gravity at the surface of the earth increase or decrease? If so, by what per cent?

If the radius of the earth shrinks by 3.5% ( mass remains constant) then how would the value of acceleration due to gravity change?

Find the height (in terms of R, the radius of the earth) at which the acceleration due to gravity becomes g/9(where g=the acceleration due to gravity on the surface of the earth) is

The ratio of the radius of the earth to that of the motion is 10. the ratio of the acceleration due to gravity on the earth to that on the moon is 6. The ratio of the escape velocity from the earth's surface to that from the moon is